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svetoff [14.1K]
3 years ago
12

Please can you help me on my other question ?

Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0
Sure Bro
Just post it on brainly.in or this app.
You might be interested in
The equation y= 39 4x describes the number of miles y that an airplane travels in x minutes. What is the constant speed of the a
7nadin3 [17]
Speed: distance traveled in a given time

y=distance ( given in miles).
x = time (given in minutes)

Speed = y/x

y = 39.4x

By rearranging this y/x =39.4 ( is the constant speed). don’t forget this is mile/minutes

There are 4 x 60 minutes in 4 hours

Hence, you are asked the distance (y) in 240 min

y = 39.4x
y = 39.4 miles/minutes x (240) minutes

y = 9456 miles
7 0
3 years ago
Which inequality is true? Use the number line to help.
jolli1 [7]

Answer:

  c. -1.5 < -0.5

Step-by-step explanation:

a. -1.5 > 0.5 . . . . false

b. -0.5 > 0 . . . . . false

c. -1.5 < -0.5 . . . TRUE

d. 1/2 > 0.5 . . . . false (these are the same number) 1/2 = 0.5

_____

In order on the number line from left to right, you will see ...

  (left end) ... -1.5 ... -0.5 ... 0 ... 0.5 ... (right end)

__

The inequality relation appropriate to these is ...

  (number on the left) < (number on the right)

Of course, this can be swapped around so you have ...

  (number on the right) > (number on the left)

4 0
3 years ago
Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has
Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

<span>Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
</span>Solving 

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

<span>AB = 6 units   BC = 11 units AC = 12.53 units
</span><span>∆XYZ  X(-10, 5), Y(-12, -2), and Z(-4, 15)
</span><span>XY = 7.14 units   YZ = 18.79 units XZ = 11.66 units</span>

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>MN = 6 units   NO = 11 units MO = 12.53 units
</span><span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).
</span><span>JK = 5 units   KL = 9 units JL = 10.30 units
</span><span>∆PQR  P(12, 3), Q(12, -2), and R(3, -2)
</span><span>PQ = 5 units   QR = 9 units PR = 10.30 units</span> 
Therefore
<span>we have the <span>∆ABC   and the </span><span>∆MNO  </span><span> 
with all three sides equal</span> ---------> are congruent  
</span><span>we have the <span>∆JKL  </span>and the <span>∆PQR 
</span>with all three sides equal ---------> are congruent  </span>

 let's check

 Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

 1)     If ∆MNO   ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC 

<span> then </span>∆MNO<span> ≅</span> <span>∆ABC  </span> 

 a)      Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>M(-9, -4)----------------->  M1(-9,4)</span>

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

 b)      Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

<span>∆M1N1O1  M1(-9, 4), N1(-3, 4), and O1(-3, 15).</span>

<span>M1(-9, -4)----------------->  M2(9,4)</span>

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

 c)   Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

<span>∆M2N2O2  M2(9,4), N2(3,4), and O2(3, 15).</span>

<span>M2(9, 4)----------------->  M3(11,6)=A</span>

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

 ∆MNO  reflection------- >  ∆M1N1O1  reflection---- > ∆M2N2O2  translation -- --> ∆M3N3O3 

 The ∆M3N3O3=∆ABC 

<span>Therefore ∆MNO ≅ <span>∆ABC   - > </span>check list</span>

 2)     If ∆JKL  -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR 

<span> then </span>∆JKL ≅ <span>∆PQR  </span> 

 d)     Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

<span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).</span>

<span>J(17, -2)----------------->  J1(2,17)</span>

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

 e)      translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

<span>∆J1K1L1  J1(2, 17), K1(2, 12), and L1(-7, 12).</span>

<span>J1(2, 17)----------------->  J2(12,3)=P</span>

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

 ∆PQR  P(12, 3), Q(12, -2), and R(3, -2)

 ∆JKL  rotation------- >  ∆J1K1L1  translation -- --> ∆J2K2L2=∆PQR 

<span>Therefore ∆JKL ≅ <span>∆PQR   - > </span><span>check list</span></span>
6 0
3 years ago
A shape is rotated counterclockwise 110 degrees about the origin. What is another way to describe the rotation?
Kitty [74]

At max a rotation can be equal to π or 180°

So if it's rotated 110° counterclockwise then it's equal to rotation of supplementary angle clockwise

Supplementary angle=180-110=70°

70° rotation clockwise

6 0
2 years ago
A railroad crossing sign has a diameter of 30 inches. what is the area of the sign?
Anna007 [38]

Answer:

706.5m^2

Step-by-step explanation:

The sign is a circle

Area of a circle is (pi)r^2

d = 30 in -> r = d/2  = 30/2 = 15

Area = 3.14 x (15)^2 = 706.5m^2

5 0
2 years ago
Read 2 more answers
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