The answer would be Sedimentary
Answer:
the sucrose mass is 264.g
Explanation:
The computation of the sucrose mass is shown below;
The Molar mass of is 342.3 g/mol
And, the molar mass of is 18g/mol
The mass of be Y
Now
The moles of is
= Mass of ÷ molar mass of
= Y ÷ 342.3 mol
And,
The moles of is
= Mass of ÷ molar mass of
= 100.0 ÷ 18
= 5.56mol
Now
The molar fraction of is
= Moles of ÷ (moles of + moles of ) = 0.124
= (Y ÷ 342.3) ÷ [(Y ÷ 342.3) + 5.56] = 0.124
Y ÷ 342.3 = 0.124 × [(Y ÷ 342.3 + 5.56]
Y = 0.124 × Y + (0.124 × 5.56 × 342.3)
Y = 269.4 g
hence, the sucrose mass is 264.g
A coarse particle has a diameter of 1x10-6m. a nanoparticle has a diameter of 1.6 x 10-9m. Calculate how many times bigger the diameter of the coarse particle is than the diameter of the nanoparticle
The answer is An Exclamatory Sentence.