Question

What is the specific latent heat of fusion for a substance that takes 550 kj to melt 14 kg at 262 K

Answer 1

Answer:

Specific latent heat = 39.3 kJ/Kg

Explanation:

Given:

Mass of the substance = 14 kg

Energy = 550 kJ

Temperature = 262 K

To determine:

The specific latent heat of the substance

Calculation:

The amount of heat (Q) required to change the phase or the physical state of a kilogram (kg) a substance at constant temperature is termed as specific latent heat.

$LatentHeat = \frac{q}{m}=KJ/Kg$

For the given substance:

$LatentHeat = \frac{550kJ}{14Kg}=39.3kJ/Kg$

Answer 2

q = mL

L = q/m = 550 kJ/14 kg = 39 kJ/kg