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3 years ago

15

What is the lengh of a arc wich is a quater of a circle and the adius of that circle is 4,8 cm

1 answer:

Serga [27]3 years ago

5 0

Answer:

eee amiga que quiere decir eso no lo estiendo

You might be interested in

Which is the solution to the inequality y+15<3

qaws [65]

Y+15<3. subtract 15 on both sides

y<-12

5 0

3 years ago

The area of a triangle that has a base of 7 and a height of 17 is:

Andru [333]

Answer:

59.5

Step-by-step explanation:

First we have to multiply 7 by 17 (7x17).

Then you have to divide it by 2.

1/2 X base x height

8 0

2 years ago

1. What is the vertex form of the equation?

sergeinik [125]

1.vertex form is $y=a(x-h)^2+k$

to get into vertex form, complete the square

$y=-x^2+12x-4$

step 1: group x terms

$y=(-x^2+12x)-4$

step 2: factor coefient in front of x^2 term

$y=-1(x^2-12x)-4$

prep for next step: take 1/2 of linear (1st dgree term) and square it

$\frac{-12}{2}=-6$ , $(-6)^2=36$

step 3: add positive and negative of that previous number inside the parenthasees

$y=-1(x^2-12x+36-36)-4$

factor perfect squaer trionmial

$y=-1((x-6)^2-36)-4$

take out that -36 by expansion

$y=-1(x-6)^2+36-4$

$y=-1(x-6)^2+32$

2. factor out the 2

$2(x^2+8x+12)$

what 2 numbers multiply to get 12 and add to get 8?

2 and 6

$2(x+2)(x+6)$

3.

for $ax^2+bx+c=0$

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

in our case

$x^2-7x-6=0$

a=1, b=-7, c=-6

$x=\frac{-(-7) \pm \sqrt{(-7)^2-4(1)(-6)}}{2(1)}$

$x=\frac{7 \pm \sqrt{73}}{2}$

so $x=\frac{7+\sqrt{73}}{2}$ and $x=\frac{7-\sqrt{73}}{2}$

4. remember that $i=\sqrt{-1}$ so $i^2=-1$

treat $i$ as a variable

$(-2i)(8i)=$

$(-2)(i)(8)(i)=$

$(-2)(8)(i)(i)=$

$(-16)(i^2)=$

$(-16)(-1)=$

[tex}16[/tex]

8 0

3 years ago

Read 2 more answers

Need help on this thank you

krok68 [10]

Answer:

a=7

Step-by-step explanation:

24^2+a^2=25^2

576+a^2=625

49=a^2

a=7

5 0

3 years ago

ch4aika [34]

The range of the function g(x) is {y : -5 < y <∞}

<h3>How to determine the range?</h3>

The function is given as:

g(x) = f(x) - 5

The above means that the minimum value of g(x) is 5 less than the minimum value of f(x)

Assume that f(x) = 0;

Then we have:

g(x) = 0 - 5

This gives

g(x) = -5

This means that g(x) cannot be less than -5

Hence, the range of the function g(x) is {y : -5 < y <∞}

Read more about range at:

brainly.com/question/10197594

#SPJ1

3 0

2 years ago