All categories

2 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics

1 answer:

Rufina [12.5K]2 years ago

8 0

Answer:

B, 600

I've attached a graph to help ya!

Hope this helps!

You might be interested in

SHOW YOUR WORK! Marking the best response with brainliest:) thank u

sdas [7]

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

The length is 3x + 7

The width is 2x + 2

The perimeter is

Simplify

6x + 7 + 4x + 4

Group like terms

6x + 4x + 7 + 4

We have the final answer as

Hope this helps you

6 0

3 years ago

PLEASE HELP!!!!! FAST!!! I’ll mark brainliest

siniylev [52]

Answer:

the third one

Step-by-step explanation:

plan A is less expensive for more than 6 features

5 0

2 years ago

Can anyone help with this?!?!

Gnom [1K]

Since y=5 is an asymptote, it means that y will approach 5 but never be 5. So you use (. Then, you see the function increasing from the asymptote so it would be (5, infinity) Choice C

5 0

3 years ago

Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)

Maurinko [17]

Answer:

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

$(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0$

Substituting the end point are

$(x-(-2))(x-4)+(y-(-2))(y-(-10))=0\\(x+2))(x-4)+(y+2))(y+10))=0\\$

Applying Distributive Property we get

$x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0$

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

6 0

2 years ago

What is the volume of this rectangular prism?

tangare [24]

180
This is because 12x5x3 = 180

5 0

2 years ago

Read 2 more answers