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KengaRu [80]
3 years ago
14

Is (4,9) a solution to the equation 3(x+2) = y ?

Mathematics
2 answers:
Mrac [35]3 years ago
8 0

Answer:

(4, 9) is not a solution to 3(x + 2) = y.

Step-by-step explanation:

3(x + 2) = y

Substitute (4, 9) into the equation.

3(4 + 2) = 9

Add the inside of the parenthesis.

3(6) = 9

Multiply.

18 ≠ 9

stepladder [879]3 years ago
5 0
(4,9) is not a solution to the equation.
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1 st 2nd and 4th are NOT parallelograms.
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write the equation for the nth term of the sequence and then find the value of the 24th term: 4, 13, 22, 31, ...
julia-pushkina [17]

Answer :

nth term

an = a1 + (n-1) d

an = 4 + (9-1) 9

an = 4 + (8)9

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Hope it helped

4 0
3 years ago
I want to be a teacher some day and i know this question----------What is -15 -(-8)=? remember a negitive plus a negitive equals
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3 years ago
Darrell has the following data:
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Step-by-step explanation:

7 0
2 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

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There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
3 years ago
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