Please help me and happy april fools day! B)
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Correct Question is: Find the illegal values of b in the fraction (2b^2 + 3b - 10)/(b^2 - 2b - 8)
illegal values are those which are not a part of Domain. In this case these will be such values which will make the denominator of the fraction zero.
So setting the denominator equal to zero, we can find these values.
Thus, b=-2 and b=4 are the illegal values for this expression
illegal values are those which are not a part of Domain. In this case these will be such values which will make the denominator of the fraction zero.
So setting the denominator equal to zero, we can find these values.
Thus, b=-2 and b=4 are the illegal values for this expression
That's just the distance between 2 points
the distance between (x1,y1) and (x2,y2) is
we can find the distance between S and Q or P and R
S and Q is (0,0) and (a,b)
distance between P and R is between(0,b) and (a,0)
so the lengths of diagonals are congruent
the distance between (x1,y1) and (x2,y2) is
we can find the distance between S and Q or P and R
S and Q is (0,0) and (a,b)
distance between P and R is between(0,b) and (a,0)
so the lengths of diagonals are congruent