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timama [110]
3 years ago
11

In the diagram below, AB = BD = BC, and mZA = 24°. Find mZC.

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

m∠C = 66°

Step-by-step explanation:

Since AB = BD, it means this triangle is an Isosceles triangle and as such;

∠BAD = ∠BDA = 24°

Thus, since sum of angles in a triangle is 180,then;

∠ABD = 180 - (24 + 24)

∠ABD = 180 - 48

∠ABD = 132°

We are told that BC = BD.

Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC

Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.

Thus;

132 = ∠BCD + ∠BDC

Since ∠BCD = ∠BDC, then

∠BCD = ∠BDC = 132/2

∠BCD = ∠BDC = 66°

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the sum of the geometric sequence is [3/2+3/8+3/32+3/128+3/512]

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the answer is

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another way to calculate it 

is through the following formula

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where 

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n----------> is the number of terms

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n=5

so

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Step-by-step explanation: we have that

[3/2,3/8,3/32,3/128,3/512]

the sum of the geometric sequence is [3/2+3/8+3/32+3/128+3/512]

=(1/512)*[256*3+64*3+16*3+4*3]

=(3/512)*[256+64+16+4]

=(3/512)*[340]

=(1020/512)

=255/128---------> 1.9922

the answer is

1.9922

another way to calculate it 

is through the following formula

∑=ao*[(1-r^n)/(1-r)]

where 

ao---------> is the first term

r----------> is the common ratio between terms

n----------> is the number of terms

ao=1.5

r=1/4-----> 0.25

n=5

so

∑=1.5*[(1-0.25^5)/(1-0.25)]-------------> 1.99

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