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3 years ago

PLS I NEED HELP WITH MATH HOMEWORK FIND THE VALUE OF THE VARIBLE

Mathematics

1 answer:

zzz [600]3 years ago

3 0

Answer:

n=46

Step-by-step explanation:

Since this is a right triangle, you are left with 90 degrees

2n-2=90

2n=92

n=46

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How would you identify a perfect square trinomial? Give an example.

belka [17]

Answer:

"Perfect square trinomials" are quadratics which are the results of squaring binomials. (Remember that "trinomial" means "three-term polynomial".)

For instance:

(x + 3)2

= (x + 3)(x + 3)

= x2 + 6x + 9

...so x2 + 6x + 9 is a perfect square trinomial.

7 0

3 years ago

Lin rode her bike 2 miles in 8 minutes. She rode at a constant speed. Complete the table to show the time it took her to travel

pantera1 [17]

Answer:

The answer is 56

Step-by-step explanation:

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2 years ago

What is the product?

ZanzabumX [31]

To get the answer to this equation you first cancel out the 6! ;)

(x^2-1)(6x-1) / (x+1)

Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1

(x^2-1^2)(6x-1) / (x+1)

Then use the difference of squares!

(x+1)(x-1)(6x-1) / (x+1)

LASTLY cancel "x+1" !

so ur answer is (x-1) (6x-1)

That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)

YW!!! ;)

6 0

3 years ago

Read 2 more answers

The body weight of a healthy 3 month-old colt should be about μ = 60 kg. (Source: The Merck Veterinary Manual, a standard refere

tatuchka [14]

Answer:

The null hypothesis will be $H_o : \mu = 60 \ kg$

The alternative hypothesis will be $H_a : \mu < 60$

The alternative hypothesis will be $H_a : \mu > 60$

The alternative hypothesis will be $H_a : \mu \ne 60$

left; right; both

Step-by-step explanation:

Considering question a

The body weight of the colt is $\mu = 60 \ kg$

The null hypothesis will be $H_o : \mu = 60 \ kg$

Considering question b

Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then

The alternative hypothesis will be $H_a : \mu < 60$

Considering question c

Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then

The alternative hypothesis will be $H_a : \mu > 60$

Considering question d

Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then

The alternative hypothesis will be $H_a : \mu \ne 60$

Considering question e

For question b , the corresponding p-value will be on the left because the average weight is less than 60 kg

For question c , the corresponding p-value will be on the right because the average weight is more than 60 kg

For question d , the corresponding p-value will be on both because the average weight is different from 60 kg

5 0

2 years ago

Jared made 4 bird houses in 3 days. How many days will it take him to make 28 bird houses.

pogonyaev

4 times 7 = 28

3 times 7 = 21

It will take him 21 days to make 28 bird houses.

6 0

3 years ago