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4 years ago

Round 34.9172 to the nearest hundredth.

Mathematics

2 answers:

Whitepunk [10]4 years ago

7 0

451.0200 because 7 is bigger than 1 so you would round that and the 7 and 2 would turn into zeros.

Nina [5.8K]4 years ago

5 0

34.92 is the answerr i think

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Please help me! I’ll name you brainiest!!!

Kamila [148]

Answer:

Step-by-step explanation:

first, put in (5x-4) for the x in g(x).

g(f(x))=(5x-4)^2 -1

now, FOIL and simplify.

25x^2-40x+16-1

25x^2-40x+15

now, plug in -1 for x.

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8 0

3 years ago

Read 2 more answers

Write a two column proof for the following conjecture. Statements and reasons

bazaltina [42]

<span>Information is given(reasons are in the parenthesis)

Angle A and angle B are supplementary. Angle B and Angle C are supplementary (given)

DC is parallel to AB (consecutive interior angles are supplementary )
BC is parallel to AD (consecutive interior angles are supplementary)

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3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$