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SashulF [63]
3 years ago
15

2. What is the reason for spherometer stands on three legs?​

Physics
2 answers:
timama [110]3 years ago
3 0

Answer:

tis unknown

Explanation:

dan dan duuun dun dun

GaryK [48]3 years ago
3 0
Spherometers have three legs that form an equilateral triangle. Recall from geometry that three points determine a plane, so the three legs will always touch the glass.
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If a scientist unknowingly breaks the law, he is guilty of _____.
Margaret [11]

Answer:

noncompliance

Explanation:

If a scientist unknowingly breaks the law, he is guilty of <u>noncompliance</u>

8 0
2 years ago
Read 2 more answers
1. Add 17.35 g, 25.6 g and 8.498 g. chaper 1 physical quantity 11class .physic​
Korvikt [17]

51.448 g is the required answer!

8 0
3 years ago
Problem 8: Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric fi
yanalaym [24]

Answer:

10581.59 V

Explanation:

We are given that

Magnetic field=B=0.65 T

Speed of electron=v=6.1\times 10^7m/s

Charge on electron, q=e=1.6\times 10^{-19} C

Mass of electron,m_e=9.1\times 10^{-31} kg

We have to find the potential difference in volts required in the first part of the experiment to accelerate electrons.

V=\frac{v^2m_e}{2e}

Where V=Potential difference

m_e=Mass of electron

v=Velocity of electron

Using the formula

V=\frac{(6.1\times 10^7)^2\times 9.1\times 10^{-31}}{2\times 1.6\times 10^{-19}}

V=10581.59 V

Hence, the potential difference=10581.59 V

8 0
2 years ago
To get off a frozen lake, a 70 kg person removes his shoe of mass 0.175 kg and throws it horizontally away from the shore at a v
MakcuM [25]

Answer:

the person will be in the shore at 10.73 minutes after launch the shoe.

Explanation:

For this we will use the law of the lineal momentum.

L_i = L_f

Also,

L = MV

where M is de mass and V the velocity.

replacing,

M_i V_i = M_{fp}V_{fp} + M_{fz}V_{fz}

wher Mi y Vi are the initial mass and velocity, Mfp y Vfp are the final mass and velocity of the person and Mfz y Vfz are the final mass and velocity of the shoe.

so, we will take the direction where be launched the shoe as negative. then:

(70)(0) = (70-0.175)(V_fp) + (0.175)(-3.2m/s)

solving for V_fp,

V_fp = \frac{(3.2)(0.175)}{69.825}

V_fp = 0.008m/s

for know when the person will be in the shore we will use the rule of three as:

1 second -------------- 0.008m

t seconds-------------- 5.15m

solving for t,

t = 5.15m/0.008m

t = 643.75 seconds = 10.73 minutes

 

3 0
2 years ago
Calculate the magnitude of the electric field 2.00 m from a point charge of 5.00 mC (such as found on the terminal of a Van de G
MakcuM [25]

Answer:

The magnitude of the electric field is 1.124 X 10⁷ N/C

Explanation:

Magnitude of electric field is given as;

E = \frac{kq}{r^2} , N/C

where;

E is the magnitude of the electric field, N/C

q is the point charge, C

k is coulomb's constant, Nm²/C²

r is the distance of the point charge, m

Given;

q = 5mC = 5×10⁻³ C

r = 2m

k = 8.99 × 10⁹ Nm²/C²

Substitute these values and solve for magnitude of electric field E

E = \frac{kq}{r^2}  = \frac{(8.99 X10^9)(5X10^{-3})}{2^2}  = 1.124 X10^7 N/C

Therefore, the magnitude of the electric field is 1.124 X 10⁷ N/C

7 0
2 years ago
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