A 0.5-kilogram piece of aluminum increases its temperature 7°C when heat energy (Q) is added. Set up the equation with the corre
1 answer:
Answer:
Heat energy (Q) added is 3150 (J) .
Explanation:
Given:
Mass of the aluminum = 0.5 kg
Change in temperature = 7°C
According to the question :
Heat energy (Q) is added up.
We have to find the equation with correct values.
We know that,Q = mCΔT m is the mass,C is the specific heat and T is the change in temperature.
Specific heat of aluminum = 900 (J/kg °C)
Plugging the values,we have :
⇒
⇒
⇒ Joules (J)
So the heat energy added (Q) = 3150 Joules.
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