Question

A 0.5-kilogram piece of aluminum increases its temperature 7°C when heat energy (Q) is added. Set up the equation with the correct values.

Answer 1

Answer:

Heat energy (Q) added is 3150 (J) .

Explanation:

Given:

Mass of the aluminum = 0.5 kg

Change in temperature = 7°C

According to the question :

Heat energy (Q) is added up.

We have to find the equation with correct values.

We know that,Q = mCΔT m is the mass,C is the specific heat and T is the change in temperature.

Specific heat of aluminum = 900 (J/kg °C)

Plugging the values,we have :

⇒ $Q=mC\Delta T$

⇒ $Q = 0.5\times 900\times 7$

⇒ $Q= 3150$ Joules (J)

So the heat energy added (Q) = 3150 Joules.