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Gemiola [76]
3 years ago
7

A 0.5-kilogram piece of aluminum increases its temperature 7°C when heat energy (Q) is added. Set up the equation with the corre

ct values.
Physics
1 answer:
mars1129 [50]3 years ago
6 0

Answer:

Heat energy (Q) added is 3150 (J) .

Explanation:

Given:

Mass of the aluminum = 0.5 kg

Change in temperature = 7°C

According to the question :

Heat energy (Q) is added up.

We have to find the equation with correct values.

We know that,Q = mCΔT m is the mass,C is the specific heat and T is the change in temperature.

Specific heat of aluminum = 900 (J/kg °C)

Plugging the values,we have :

⇒ Q=mC\Delta T

⇒ Q = 0.5\times 900\times 7

⇒ Q= 3150 Joules (J)

So the heat energy added (Q) = 3150 Joules.

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