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ICE Princess25 [194]
3 years ago
12

A sky diver steps from a high-flying helicopter. if there were not air resistance, how fast would she be falling at the end of a

12 second jump?
Physics
1 answer:
Rama09 [41]3 years ago
8 0

If there is no air resistance and the body, in this case the sky diver simply falls from the helicopter then, the motion can be described as a free-falling body. The equation that would allow us to determine the speed of the body at any time, t is,

<span>                                    v(t)  = vo + gt</span>

<span>where v(t) is the unknown velocity, vo is the initial velocity which is equal to zero and g is the acceleration due to gravity which is equal to 9.8 m/s2.</span>

Substituting the known values,

<span>                                    v(t) = 0 + (9.8 m/s2)(12s)</span>

<span>                                                v(t) = 117.6 m/s</span>

<span>Hence, the speed of the sky diver at the end of 12 second is approximately 117.6 m/s.  </span>

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