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Kay [80]
3 years ago
5

ANY ONE TALK i'm so bored

Physics
2 answers:
MaRussiya [10]3 years ago
7 0

Answer:

So am I

Explanation:

Anuta_ua [19.1K]3 years ago
5 0

Answer:

<h3>I am also bored. ❤❤❤</h3>

Explanation:

<h3>Please mark my answer as a brainliest. </h3>
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In which arrangement of magnets will all the magnets attract
Elodia [21]

when they all are opisite

IDK I just guess

7 0
3 years ago
Read 2 more answers
Based on Kepler's work, which best describes the orbit If a planet around the Sun?
krek1111 [17]

Answer:

an ellipse with the Sun at one focus  or D

Explanation:

Answer for edgenuity

7 0
4 years ago
A 160.-kilogram space vehicle is traveling along a
mario62 [17]

If the object is moving in a straight line at a constant speed, then that's
the definition of zero acceleration.  It can only happen when the sum of
all forces (the 'net' force) on the object is zero.

And it doesn't matter what the object's mass is.  That argument is true
for specks of dust, battleships, rocks, stars, rock-stars, planets, and
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4 0
3 years ago
How many amps are there in the current of a circuit if the voltage source is 140v and the resistance is 2 ohms?
VLD [36.1K]
Voltage (V)= Current (I) * Resistance (R)
I=V/R=140/2=70A

Hope this helps!
7 0
3 years ago
You stand on a merry-go-round which is spinning at f = 0:25 revolutions per second. You are R = 200 cm from the center. (a) Find
ivanzaharov [21]

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

<u>ω = 1.57 rad/s </u>

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

<u>ac = 4.92 m/s² </u>

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

<u>μs = 0.5</u>

7 0
3 years ago
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