Answer:
see attachment
Step-by-step explanation:
Answer:
Step-by-step explanation:
-3x+10=21
-3x=21-10
-3x=11
x=11/-3
x=- 11/3
Answer:
cement by 5 Kg
Step-by-step explanation:
add the parts of the ratio, 5 + 4 + 1 = 10 parts
Divide the quantity of concrete by 10 to find the value of one part of the ratio.
110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus
5 parts = 5 × 11Kg = 55Kg ← cement required
4 parts = 4 × 11Kg = 44Kg ← sand required
1 part = 11Kg ← gravel required
He requires 55Kg of concrete but only has 50Kg.
He requires 44Kg of sand and has 55Kg
He requires 11Kg of gravel and has 15Kg
Thus he is 5Kg short of cement.
Answer:
x = 2
Step-by-step explanation:
The relevant rule of logarithms is ...
log(a/b) = log(a) -log(b)
This lets us combine the logs on the left to get ...
log((6 +7x)/(3x -2)) = log(5)
Taking anti-logs gives ...
(6 +7x)/(3x -2) = 5
6 +7x = 5(3x -2) . . . . . multiply by (3x -2)
7x +6 = 15x -10 . . . . . eliminate parentheses
8x = 16 . . . . . . . . . . . add 10-7x to both sides
x = 2 . . . . . . . . . . . . . divide by 8
The solution is x = 2.
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The graph shows the left side of the equation is equal to the right side for x=2.