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Romashka-Z-Leto [24]
2 years ago
13

Make a flow chart showing that the triangles below are similar. NO LINKS OR CRAZY LANGUAGES.!!!!!!​

Mathematics
1 answer:
pantera1 [17]2 years ago
8 0

Answer: See the attached image

You have the correct idea for the boxes you've filled out. For the first three boxes in column 1, I would be specific which segments you are dividing. So for instance, in the first box, it would be EG/EB = 55/11 = 5. Then the second box would be EF/EC = 35/7 = 5, and so on. The order of the boxes doesn't matter. The three boxes then combine together to help show that the triangles are similar. Specifically \triangle EFG \sim \triangle ECB. The order of the letters is important to help show how the angles pair up and how the sides pair up. We use the SSS similarity theorem here.

The second problem is the same idea, but we use one pair of congruent angles. So we'll use the SAS similarity theorem this time.

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The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Pls help the person with the correct answer will get a brainliest
Flauer [41]
D) Daniel’s Brick
This is because it has the most bricks close to 2.5 inches.
7 0
2 years ago
Solve each equation write each equation in simplest form 7x/8=21
AveGali [126]
7x / 8 = 21
7x = 8*21
x = 24
8 0
3 years ago
The parent of a constant function is: a. f(x)=c. b. f(x)=cx. c. f(x)= x​
Sonja [21]

Answer:

For what value of the constant c is the function f continuous on (-infinity, infinity)?

f(x)

=cx2 + 8x    if x < 3

=x3 ? cx if x ? 3

Step-by-step explanation:

7 0
3 years ago
Fhrjmfkfkjdjdkjsjjxbdhdjdiu
Nat2105 [25]

Answer:

-25

Step-by-step explanation:

-35 · (\frac{5}{7})

-\frac{175}{7}        Multiply the whole number by the numerator

-25         Then simplify by dividing 175 ÷ 7

5 0
3 years ago
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