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Romashka-Z-Leto [24]
3 years ago
13

Make a flow chart showing that the triangles below are similar. NO LINKS OR CRAZY LANGUAGES.!!!!!!​

Mathematics
1 answer:
pantera1 [17]3 years ago
8 0

Answer: See the attached image

You have the correct idea for the boxes you've filled out. For the first three boxes in column 1, I would be specific which segments you are dividing. So for instance, in the first box, it would be EG/EB = 55/11 = 5. Then the second box would be EF/EC = 35/7 = 5, and so on. The order of the boxes doesn't matter. The three boxes then combine together to help show that the triangles are similar. Specifically \triangle EFG \sim \triangle ECB. The order of the letters is important to help show how the angles pair up and how the sides pair up. We use the SSS similarity theorem here.

The second problem is the same idea, but we use one pair of congruent angles. So we'll use the SAS similarity theorem this time.

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Convert the following to standard form <br><br>y=2/5 x - 1/3​
Afina-wow [57]

<u>Given </u><u>:</u><u>-</u>

  • y = 2/5x - 1/3

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • To convert the given equation into standard form.

<u>Solution</u><u> </u><u>:</u><u>-</u>

As we know that the standard form of the line is ,

\sf\longrightarrow ax + by + c = 0

So the given equation is ,

\sf\longrightarrow y = 2/5x -1/3

\sf\longrightarrow y = 6x - 5/15

\sf\longrightarrow 15y = 6x - 5

\sf\longrightarrow 6x -15y -5 = 0

<u>Hence</u><u> the</u><u> required</u><u> </u><u>equation</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>6</u><u>x</u><u> </u><u>-15y-5=</u><u>0</u><u>.</u>

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3 years ago
If the angles is 180 and there is 3 parts (3x+94) and (x+36) and (2x-4) what is x
DiKsa [7]
Hehe, I thought I'd get this one wrong, but x=10. Remember, that a straight angle must add up to 180 degrees. So I added all the angles; (3x+94)+(x+36)+(2x-4)=180. I took away the parentheses having 3x+94+x+36+2x-4=180. Remember from Algebra 1, to simplify terms, we add the polynomials. 94+36-4=126. 3x+x+2x= 6x. Our simplified equation is 120+6x=180. Now we can answer. 180-120=60. 60=6x. So therefore, for all x, x equals 10.
3 0
4 years ago
A sum of 6(3x+8)+32+12x in different ways
Lemur [1.5K]
First you have multiply 6 by both 3x and 8
6*3x = 18x
6*8= 48
18x + 48 + 32 + 12x
now combine like terms
18x + 12x = 30x
48 + 32 = 80
so 30x + 80 is your answer
8 0
4 years ago
OMG PLS HELP ME!!!!!! I NEED THIS ASAP!!! 100 PTS!!!!!!!<br><br> (its in the pic)
Rainbow [258]

By algebra properties we find the following relationships between each pair of algebraic expressions:

  1. First equation: Case 4
  2. Second equation: Case 1
  3. Third equation: Case 2
  4. Fourth equation: Case 5
  5. Fifth equation: Case 3

<h3>How to determine pairs of equivalent equations</h3>

In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:

First equation

(7 - 2 · x) + (3 · x - 11)

(7 - 11) + (- 2 · x + 3 · x)

- 4 + (- 2 + 3) · x

- 4 + (1) · x

- 4 + (5 - 4) · x

- 4 - 4 · x + 5 · x

- 4 · (x + 1) + 5 · x → Case 4

Second equation

- 7 + 6 · x - 4 · x + 3

(6 · x - 4 · x) + (- 7 + 3)

(6 - 4) · x - 4

2 · x - 4

2 · (x - 2) → Case 1

Third equation

9 · x - 2 · (3 · x - 3)

9 · x - 6 · x + 6

3 · x + 6

(2 + 1) · x + (14 - 8)

[1 - (- 2)] · x + (14 - 8)

(x + 14) - (8 - 2 · x) → Case 2

Fourth equation

- 3 · x + 6 + 4 · x

x + 6

(5 - 4) · x + (7 - 1)

(7 + 5 · x) + (- 4 · x - 1) → Case 5

Fifth equation

- 2 · x + 9 + 5 · x  + 6

3 · x + 15

3 · (x + 5) → Case 3

To learn more on algebraic equations: brainly.com/question/24875240

#SPJ1

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1 year ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

4 0
3 years ago
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