2 years ago

Can someone please be indepth

Mathematics

1 answer:

Sidana [21]2 years ago

8 0

Pretty sure it’d be (3, 14)

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If DEF and MNO are two triangles such that DE=MN and EF=NO, which of the following would be sufficient to prove that triangles a

Delvig [45]

Answer:

D. ∠E ≅ ∠N

Step-by-step explanation:

The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...

∠E ≅ ∠N

Then the SAS congruence postulate can be claimed.

<em>Additional comment</em>

The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.

3 0

2 years ago

Ements

kakasveta [241]

Here's li $^{}$ nk to the answer:

bit. $^{}$ ly/3fcEdSx

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3 years ago

Circle F has a diameter of 36m and = 240o. Find the length of . Leave your answer in terms of pi.

andrezito [222]

Answer:

So, the arc length is $24\pi$

Step-by-step explanation:

We are given

diameter =36m

so, we can find radius

$r=\frac{36}{2}=18m$

and angle as

$\theta=240$

Since, it is in degree

so, we can change it in radian

$\theta=240\times \frac{\pi}{180}$

$\theta=\frac{4\pi}{3}$

now, we can find arc length

$L=r\times \theta$

now, we can plug values

$L=18\times \frac{4\pi}{3}$

$L=24\pi$

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3 years ago

What’s 5 equivalent ratios to 27:9

Feliz [49]

3:1

6:2

24:8

15:5

30:10

hope this helps, have a great day :)

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3 years ago

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Polygon P'Q'R'S'T' shown on the grid below is an image of polygon PQRST after dilation with a scale factor of 3, keeping the ori

Allushta [10]

Answer:

D is the answer

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3 years ago

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