A) The length of the longer leg is x-1
b) Based on the area, the other leg is 2*30/(x -1). Based on the Pythagorean theorem, the other leg is √(x^2 -(x -1)^2).
c) Equating the two expressions for the shorter leg, we have
.. 60/(x -1) = √(2x -1)
.. 3600/(x -1)^2 = (2x -1)
.. (2x -1)(x^2 -2x +1) = 3600
.. 2x^3 -5x^2 +4x -3601 = 0
d) There is one positive real root, at x=13. A graphical solution works well.
The three sides of the triangle are 5 in, 12 in, 13 in.
_____
5-12-13 is a well-known Pythagorean triple. It is the next smallest one after 3-4-5.
Answer:
7 inches
Step-by-step explanation:
First you have to find the average height of each class.
4th Grade:
56, 47, 54, 51, 53, 58, 48, 54, 46, 53
Then you have add it all up and divide it by how many students there are.
56 + 47 + 54 + 51 + 53 + 58 + 48 + 54 + 46 + 53 = 520
520 ➗10= 52
Same process for the 7th Grade.
You end up getting 52 and 59. You then Subtract it to get the answer to the question.
52 - 59= 7 inches
Answer:
Step-by-step explanation:
Given
Required
Solfe for x and y
Subtract both equations
Divide by -1
Substitute in
Collect like terms
Answer:
1
Step-by-step explanation:
3 - (4) 1/2
3 - 2
= 1
a½+b½-c½=0
a½+b½=c½
Squaring on both sides,
(a½+b½) ²=c½×²
a+b+2a½b½=c
a+b-c= -2a½b½
Again squaring on both sides,
(a+b-c) ²=(-2a½b½) ²
= 4ab.