37 and 1 / 4 = 37 * 6 = 74 * 3 = 222
Hi There!
Step-by-step explanation:
5/45 = 1/9
Answer:
A ratio that is equivalent to 5/45 is 1/9!
Hope This Helps :)
Answer:
0.06597
Step-by-step explanation:
Given that thirty-seven percent of the American population has blood type O+
Five Americans are tested for blood group.
Assuming these five Americans are not related, we can say that each person is independent of the other to have O+ blood group.
Also probability of any one having this blood group = p = 0.37
So X no of Americans out of five who were having this blood group is binomial with p =0.37 and n =5
Required probability
=The probability that at least four of the next five Americans tested will have blood type O+
= ![P(X\geq 4)\\= P(X=4)+P(x=5)\\= 5C4 (0.37)^4 (1-0.37) + 5C5 (0.37)^5\\= 0.06597](https://tex.z-dn.net/?f=P%28X%5Cgeq%204%29%5C%5C%3D%20P%28X%3D4%29%2BP%28x%3D5%29%5C%5C%3D%205C4%20%280.37%29%5E4%20%281-0.37%29%20%2B%205C5%20%280.37%29%5E5%5C%5C%3D%200.06597)
Answer: Distance around a circle
are you in college?
Answer:
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 36, \sigma = 5](https://tex.z-dn.net/?f=%5Cmu%20%3D%2036%2C%20%5Csigma%20%3D%205)
The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{40 - 36}{5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B40%20-%2036%7D%7B5%7D)
![Z = 0.8](https://tex.z-dn.net/?f=Z%20%3D%200.8)
has a pvalue of 0.7881.
1 - 0.7881 = 0.2119
So 21.19% of the students use the computer for longer than 40 minutes.
Out of 10000
0.2119*10000 = 2119
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.