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love history [14]

2 years ago

11

Please help honestly loving you helpers.. IT SAYS: what is the surface area of this figure/Remeber there is a difference between

the surface area the lateral surface area. This is specific to the surface Area. Remeber to show your work’

2 answers:

julsineya [31]2 years ago

8 0

The answer is 3 because I am just trying to get points bye luv yah

Natalka [10]2 years ago

8 0

The answer should be 460

SA= 10x10+6(1/2x12x10) would be the equation, solve and you’d end up with 460! I’m not positive this is the answer, just based off of what I remeber

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A motor boat travels 60 miles down a river in three hours but takes five hours to return upstream. Find the rate of the boat in

Kryger [21]

Answer:

boat: 16 mph
current: 4 mph

Step-by-step explanation:

speed = distance / time

The rate downriver is (60 mi)/(3 h) = 20 mi/h.

The rate upriver is (60 mi)/(5 h) = 12 mi/h.

The rate of the boat in still water is the average of these:

(20 +12)/2 mi/h = 16 mi/h

The rate of the current is the difference between the boat speed and actual speed:

16 mi/h - 12 mi/h = 4 mi/h

3 0

3 years ago

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

So

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

3 years ago

Solve algebraically for x and explain each step( using mathematical vocbuary) for the following: 2(x+5)+ 3x = 30

Lelu [443]

First do distributive property
2x + 10 + 3x = 30
Now combine like terms
5x + 10 = 30
Subtract 10 from both sides
5x = 20
Divide both sides by 5
x = 4

8 0

3 years ago

Penny and her two friends each ate 1/6 of cake . how much cake did they eat

Hoochie [10]

They ate 1/3 of the cake

4 0

3 years ago

Read 2 more answers

The school that Michael goes to is selling tickets to a dance. On the first day of ticket sales the school sold 3 staff tickets

Minchanka [31]

The price of a staff ticket and the price of a student ticket is $8 and $14

Given:

Day 1:

Number of staff tickets sold = 3

Number of students tickets sold = 1

Total revenue day 1 = $38

Day 2:

<em>Number of staff tickets sold</em> = 3

<em>Number of students tickets sold</em> = 2

<em>Total revenue day</em> 2 = $52

let

<em>cost of staff tickets</em> = x

<em>cost of students tickets</em> = y

The equation:

<em>3x + y = 38 (1)</em>

<em>3x + y = 38 (1)3x + 2y = 52 (2)</em>

subtract (1) from (2)

2y - y = 52 - 38

y = 14

substitute y = 14 into (1)

3x + y = 38 (1)

3x + 14 = 38

3x = 38 - 14

3x = 24

x = 24/3

x = 8

Therefore,

cost of staff tickets = x

= $8

cost of students tickets = y

= $14

Read more:

brainly.com/question/22940808

8 0

3 years ago