Ask question

Ask question

All categories

MA_775_DIABLO [31]

3 years ago

8

Brainly is the reward ! please help

1 answer:

GrogVix [38]3 years ago

8 0

What do you do hear......

You might be interested in

the mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.5 %. assume

zhuklara [117]

Given:
Population proportion, $\mu _{p}$ = 57% = 0.57
Population standard deviation, σ = 3.5% = 0.035
Sample size, n = 40
Confidence level = 95%

The standard error is
$SE_{p} = \sqrt{ \frac{p(1-p)}{n} } = \sqrt{ \frac{0.57*0.43}{40} } =0.0783$

The confidence interval is
$\hat{p} \pm z^{*}SE_{p}$
where
$\hat{p}$ = sample proportion
z* = 1.96 at the 95% confidence lvvel

The sample proportion lies in the interval
(0.57-1.96*0.0783, 0.57+1.96*0.0783) = (0.4165, 0.7235)

Answer: Between 0.417 and 72.4), or between (41% and 72%)

8 0

3 years ago

. A grocery store clerk put only packages of flour tortillas and packages of corn tortillas on a shelf. The ratio of the number

KengaRu [80]

Answer: It should be 18...(Multiple of 9)

Step-by-step explanation:

3 0

3 years ago

Four and eight tenths minus two and five tenths equals− two and eight tenths

Dima020 [189]

Answer:

it's two and three tenths / option a

Step-by-step explanation:

4-2 = 2

8-5 = 3

3 0

2 years ago

Which is a multiple of 15?<br>a.1<br>b.5<br>c.h<br>d.15

lakkis [162]

15 is you answer sir. the multiples are 15,30,45,60,75<span>,90,105,120,135,150,165,180,195,210,225,240,255,270,285,300,315</span>

4 0

3 years ago

Read 2 more answers

HELP ME PLEASE!

shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

Let

x------> size of the event space

y-----> size of the sample space

so

$P=\frac{x}{y}$

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

<em>Find the area of black circle</em>

$r=3/2=1.5\ units$

$x=(3.14)(1.5)^{2} =7.065\ units^{2}$

<em>Find the total area of the square target</em>

$y=9^{2}=81\ units^{2}$

Find the probability

$P=\frac{7.065}{81}=0.0872$

Convert to percentage

$0.0872*100=8.72\%$

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

<em>Find the area of the white portion</em>

The area is equal to the area of the square minus the area of the circle

$x=81-7.065=73.935\ units^{2}$

Find the probability

$P=\frac{73.935}{81}=0.9128$

Convert to percentage

$0.9128*100=91.28\%$

The probability is closer to 1, because is greater than 50%

4 0

3 years ago