Given that,
KM bisects ∠LKJ.
m∠LKM = 4x + 12 and m∠MKJ = 6x - 6
To find,
The value of x.
Solution,
As KM bisects ∠LKJ. It would mean that,
m∠LKM = m∠MKJ
Putting the above values,
4x+12=6x-6
We can solve the above equations as follows :
4x-6x=-12-6
-2x=-18
x=9
Therefore, the value of x is equal to 9.
Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Answer:
Your answer is B
Step-by-step explanation:
6.14 Checkpoint: Systems of Linear Inequalities
I took the test.
Answer:
2.93
Step-by-step explanation:
I guessed and got it right lol
Answer:8.5
Step-by-step explanation:
Pythagorean Theorem
A
a^2 + b^2 = c^2
3^2 + 8^2 = c^2
9 + 64 = c^2
73 = c^2
C= Sqrt (73)
C = 8.5
