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12345 [234]
2 years ago
14

. What is the GCF of the expression: 28xy-14X

Mathematics
1 answer:
Tamiku [17]2 years ago
3 0

Answer:

14 x

Step-by-step explanation:

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a poll shows that 64% of americans personally worry a great deal about federal spending and the budget deficit.
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In the research, it should be noted that this is a Proportion, because worry or not worry is categorical

<h3>What is a proportion?</h3>

A population proportion is the percentage of the population that possesses a particular trait.

For illustration, suppose there are 1,000 people in the population and 237 of them have blue eyes. There are 237 blue eyed people out of every 1,000 people, or 237/1000.

Therefore, it should be noted that this is a Proportion, because worry or not worry is categorical.

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brainly.com/question/968894

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A poll shows that 64% of Americans personally worry a great deal about federal spending and the budget deficit. State whether the parameter of interest is a mean or a proportion.

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1 year ago
Solve the given inequality and graph the solution on a number line.
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

7 0
3 years ago
I need help please and thank you
Ivenika [448]

Answer

263/999                                                                                                                                                          

Step-by-step explanation:

3 0
2 years ago
A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0
3 years ago
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