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hjlf
3 years ago
5

write the equation of a line in slope intercept form that has a slope of 2/7 and has a y-intercept of 9

Mathematics
1 answer:
Rama09 [41]3 years ago
4 0

Answer:

y=2/7x+9

Step-by-step explanation:

Slope-intercept form is written y=mx+b.

y= also known as f(x), and is always by itself in slope-intercept form.

m= the slope.

x= the variable written to the right of the slope.

b= the y-intercept.

We know that the slope is 2/7 and the y-intercept in the equation is 9. Therefore, we can plug these numbers into the equation. So...

y=2/7x+9

is the correct equation written in slope-intercept form.

Hope this helps!! Have an amazing day (^人^)

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Solve by using the perfect squares method.
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Now, sing the formula (a + b)² = a² + 2ab + b² , we get,

(x + 8)² = 0

Square rooting on both sides, we get,

x + 8 = √0

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3 0
3 years ago
Read 2 more answers
Consider the vectors a =3i +j −k, b =i +j +4k, c=i +3j +k, d =−i −3j +k, g =−3i −j +k. Which pairs (if any) of these vectors are
11111nata11111 [884]

Answer:

a and b are perpendicular to each other, as are b and d, b and g

Step-by-step explanation:

To check whether two vectors are perpendicular to each other, we need the angle between these vectors to be 90 degrees.

We can find the angle between to vectors a and b from the following relation:

The cosine of the angle \theta between two vectors is equal to the dot product of this vectors divided by the product of vector magnitude.

So

cos(\theta) = \frac{a.b}{|a||b|}

cos(90) = 0, so when the dot product between vectors a and b is 0, it means that these vectors are perpendicular to each other.

Now, for your exercise, let's compute the dot product between these vectors.

-----------

a.b = (3,1,-1).(1,1,4) = 3+1-4 = 0

So a and b are perpendicular to each other.

------------

a.c = (3,1,-1).(1,3,1) = 3+3-1 = 5

a and c are not perpendicular to each other.

--------------

a.d = (3,1,-1).(-1,-3,1) = -3-3-1 = -7

So not perpendicular

---------------

a.g = (3,1,-1).(-3,-1,1) = -9-1-1 = -11

Not

-----------------

b.c = (1,1,4).(1,3,1) = 1+3+4 = 8

Not

------------------

b.d = (1,1,4).(-1,-3,1) = -1 -3 +4 = 0

b.d = 0, so b and d are perpendicular to each other

--------------------

b.g = (1,1,4).(-3,-1,1) = -3-1+4 = 0

b.g = 0, perpendicular

---------------------

c.d = (1,3,1).(-1,-3,1) = -1-9+1 = -9

No

-----------------------

c.g = (1,3,1).(-3,-1,1) = -3-3+1 = -5

No

------------------------

d.g = (-1,-3,1).(-3,-1,1) = 3+3+1 = 7

No

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Answer:

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Step-by-step explanation:

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