(√5 + 3)² / √20=
((√5 + 3)² / √20)(√20/√20)=
(√20(√5 + 3)²) / (√20)²=
√20(5+6√5+9) /20=
√20 (14+6√5) /20=
(14√20 +6√100) /20=
(14√20 +60) / 20=
(14(√4√5) + 60) /20=
(14(2)(√5)+60) / 20=
(28√5+60) /20=
(7√5+15) / 5
Answer:(√5 + 3)² / √20= <span>(7√5+15) / 5</span>
Answer:
uhh.... you are missing some part of your question
Step-by-step explanation:
Answer:
6.3 units (nearest tenth)
Step-by-step explanation:
![\boxed{Distance \: between \: 2 \: points = \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } }](https://tex.z-dn.net/?f=%5Cboxed%7BDistance%20%5C%3A%20between%20%5C%3A%202%20%5C%3A%20points%20%3D%20%20%5Csqrt%7B%20%7B%28x1%20-%20x2%29%7D%5E%7B2%7D%20%2B%20%20%7B%28y1%20-%20y2%29%7D%5E%7B2%7D%20%20%7D%20%7D)
Using the formula above,
distance between (-8, 6) and (-6, 0)
![= \sqrt{ {[ - 8 - ( - 6)]}^{2} + {(6 - 0)}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%5B%20-%208%20-%20%28%20-%206%29%5D%7D%5E%7B2%7D%20%20%2B%20%20%7B%286%20-%200%29%7D%5E%7B2%7D%20%7D%20)
![= \sqrt{ {( - 8 + 6)}^{2} + {(6 - 0)}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%28%20-%208%20%2B%206%29%7D%5E%7B2%7D%20%20%2B%20%20%7B%286%20-%200%29%7D%5E%7B2%7D%20%7D%20)
![= \sqrt{ {( - 2)}^{2} + 6^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%28%20-%202%29%7D%5E%7B2%7D%20%2B%206%5E%7B2%7D%20%20%7D%20)
![= \sqrt{4 + 36}](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B4%20%2B%2036%7D%20)
![= \sqrt{40}](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B40%7D%20)
= 6.3 units (nearest tenth)