Answer:
At the point where x = 2.
Step-by-step explanation:
First find the derivative which gives us the gradient of the tangent at any point on the curve:
y = 5x^2 - 16x
y' = 5*2 x^(2-1) - 16 x(1-1)
y' = 10x - 16.
y' is the gradient at point of coordinate x.
So when the gradient = 4:
4 = 10x - 16
10x = 20
x = 2.
x=2
(1,-1)
-2x-1 = x+2
-3x = 3
x = -1
substitute
y = (-1) + 2
y = 1
point: (1,-1)
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5 goes into 100 twenty times, so 20% is the answer
hope it helps! :)
