Answer:
At the point where x = 2.
Step-by-step explanation:
First find the derivative which gives us the gradient of the tangent at any point on the curve:
y = 5x^2 - 16x
y' = 5*2 x^(2-1) - 16 x(1-1)
y' = 10x - 16.
y' is the gradient at point of coordinate x.
So when the gradient = 4:
4 = 10x - 16
10x = 20
x = 2.
x=2
Polynomial equation solver
x-3=3x-2
Standard form:
−2x − 1 = 0
Factorization:
−(2x + 1) = 0
Solutions:
x = −1
2
= -0.5
I think x = 1.5
23 - 17 = 6
6 ÷ 4 = 1.5
