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artcher [175]
2 years ago
10

108 identical books have a mass of 30 kg.Find

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
4 0

Answer:

41.67 kg

72 books

Step-by-step explanation:

mass of 150 books = 150/108 × 30 kg

= 41.67 kg

number of books = 20/30 × 108 books

= 72 books

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Sales of 10 000 increase by 65 each year​
lorasvet [3.4K]

Answer:

Whats the question

Step-by-step explanation:

also if you are looking for the unit rate its <u><em>153.846...</em></u>

or if you are looking for how many in 2 years then <u><em>650,000</em></u>

<u><em>Hope this helps </em></u>

<u><em>Have a nice day</em></u> :)

3 0
3 years ago
Read 2 more answers
If f(x) = 5x - 11, find f(-2m + 5)
sukhopar [10]

f(-2m + 5)=5(-2m+5)-11=-10m+25-11=-10m+14

8 0
3 years ago
A credit union client deposits $3,300 in an account earning 6.5% interest, compounded annually. What will the balance of the acc
astra-53 [7]

Answer:

The balance of account at the end of 36 years is $31,849.29

Step-by-step explanation:

We are given the following in the question:

P = $3,300

r = 6.5% = 0.065

t = 36 years

The compound interest is given by:

A = p\bigg(1+\dfrac{r}{n}\bigg)^{nt}

where A is the amount, p is the principal, r is the interest rate, t is the time in years and n is the nature of compound interest.

Since interest is compounded annualy we use n = 1

A = 3300\bigg(1+\dfrac{0.065}{1}\bigg)^{36}\\\\A = \$31,849.29

Thus, balance of account at the end of 36 years is $31,849.29

6 0
3 years ago
What is 7/10 - 1/10 in its simplest form
Elenna [48]
3/5 cause you get the lowest common denominator
4 0
2 years ago
Read 2 more answers
Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
3 years ago
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