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alexandr1967 [171]
3 years ago
5

How many books are on each shelve if there are 64 books on 4 shelves?

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

In each shelves there are 64/4 books I.e. 16.

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The two linear functions f(x) and g(x) are shown below.<br> Which of the following is true
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Answer:

C}

Step-by-step explanation:

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Which linear function includes the points (3,9) and (-2,-11)
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General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (3,9),\ (-2,-11)\ into\ equation\\\\ \left \{ {{9=3a+b}\ \ \ \ \atop {-11=-2a+b\ |*-1}} \right.\\\\ \left \{ {{9=3a+b}\ \ \ \ \atop {11=2a-b}} \right.\\+----\\\\Addition\ method\\\\20=5a\ \ |:5\\\\a=4\\ b=9-3a\\b=9-3*4=9-12=-3\\\\Answer\ y=4x-3&#10;
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3 years ago
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Simplify negative 8 over 3 divided by negative 2 over 6..
zavuch27 [327]

-9/3 / -2/6

= -9/3*6/-2

=-54/-6

=9

7 0
3 years ago
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G verify that the divergence theorem is true for the vector field f on the region
Alenkasestr [34]
\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1

Converting to spherical coordinates, we have

\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi

On the other hand, we can parameterize the boundary of E by

\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle

with 0\le u\le2\pi and 0\le v\le\pi. Now, consider the surface element

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv
=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi

as required.
3 0
3 years ago
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