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valentina_108 [34]

3 years ago

10

I need help with this question can some please help me !

1 answer:

nalin [4]3 years ago

6 0

Answer:

you just shoed the answers

Step-by-step explanation:

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What is the relationship between the lines determined by the following two equations?

oksano4ka [1.4K]

Answer:

C. They are the same line.

Step-by-step explanation:

In order to compare the linear equations given, they need to be in the same form. The best form in order to evaluate slope and y-intercept is slope-intercept form, y = mx + b. Since the second equation is already in slope-intercept form, we need to use inverse operations to convert the first equation:

6x - 2y = 16 ---- 6x - 2y - 6x = 16 - 6x ---- -2y = -6x + 16

-2y/-2 = -6x/-2 + 16/-2

y = 3x - 8

Since both equations are in the form y = 3x - 8, then they are both the same line.

4 0

3 years ago

What is the slope of the line?

avanturin [10]

3/4 To find the slope of a line you need to do rise/run. you find two solid points meaning find two points are exactly on a intersection. Then you count up how much it needs to the point then count across to the next point

8 0

2 years ago

Read 2 more answers

Expand 4(z+6) into the simplest form.

Ratling [72]

4z + 24 is the answer

4 0

3 years ago

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

so

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

3 years ago

If you need to divide 2/3 by 4/5 , why is it easier to use an equation than to use a model

Kryger [21]

Now you see when you use a model it is harder kepause........

8 0

3 years ago