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Goshia [24]
4 years ago
9

What is the x-component of the force on the charge located at x = 8 cm given that q = 1.1 μC in N?

Physics
1 answer:
jonny [76]4 years ago
6 0

Answer:

Answer is = 12.3 x 10^6 N

Explanation:

We need to calculate force on the charge which is in Newtons:

Formula is = K q1q2/r^2

k is constant depeneds on the permitivity of the medium and its value is 9x10^9 Nm^2/C^2

q1 and q2 are charges and r is the distance between these two charges so just by putting values we get F= 9x10^9 x 1.1x10^-6/(8x10^-2)^2 (we get the above answer in newton)

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Fermi energy of conduction electrons in silver is 0.548 J. Calculate the number of such electrons in unit cm3
ICE Princess25 [194]

Answer:

n=1.86*10^{-30}m^3

Explanation:

From the question we are told that:

Fermi energy of conduction electrons E_f=0.548J

Generally the equation for Fermi energy is mathematically given by

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

Where

h= Planck's constant

 {n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}

 {n^{2/3}}=\frac{0.548J}{3.62*10^{-19}}

 n=(1.51*10^{-20})^{3/2}

 n=1.86*10^{-30}m^3

3 0
3 years ago
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Varvara68 [4.7K]

The answer to your question is,

4 kilometers north

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3 years ago
How is the frequency of a wave measured?
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D. How high do the sound waves go
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The invention of the microscope made it possible for people to discover
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A tank, shaped like a cone has height 12 meter and base radius 1 meter. It is placed so that the circular part is upward. It is
Temka [501]

Answer:

376966.991 Joules

Explanation:

Given that :

the height = 12  m

Let assume the tank have a thickness  = dh

The radius of the tank by using the concept of similar triangle is :

\dfrac{1}{r} = \dfrac{12}{h}

r = \dfrac{h}{12}

The area of the tank = \mathbf{\pi r^2}

The area of the tank = \mathbf{\pi( \dfrac{h}{12})^2}

The area of the tank = \mathbf{ \dfrac{\pi}{144}h^2}

The volume of the tank is  = area × thickness

= \mathbf{ \dfrac{\pi}{144}h^2 \  dh}

Weight of the element = \rho_ g * volume

where;

\rho_g = density of water ; which is given as 10000 N/m³

So;

Weight of the element = \mathbf{ 10000 *\dfrac{\pi}{144}h^2 \  dh}

Weight of the element = \mathbf{69.44 \ \pi  \ h^2 \  dh}

However; the work required to pump this water = weight × height  rise

where the height rise = 12 - h

the work required to pump this water  = \mathbf{69.44 \ \pi  \ h^2 \  dh}(12 - h)

the work required to pump this water  = \mathbf{69.44 \pi (12h^2-h^3)dh}

We can determine the total workdone by integrating the work required to pump this water

SO;

Workdone = \mathbf{\int\limits^{12}_0 {69.44 \pi(12h^2-h^3)} dh}

= \mathbf{ 69.44 \pi \int\limits^{12}_0 {(12h^2-h^3)} dh}

=  \mathbf{ 69.44 \pi[ \frac{12h^3}{3}-  \frac{h^4}{4}]^{12}}_0} }

= \mathbf{69.44 \pi [ \frac{12^4}{3}-\frac{12^4}{4}]}

= \mathbf{69.44 \pi*12^4 [ \frac{4-3}{12}]}

= \mathbf{69.44 \pi*12^4 *\frac{1}{12}}

= 376966.991 Joules

6 0
3 years ago
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