Question

Fermi energy of conduction electrons in silver is 0.548 J. Calculate the number of such electrons in unit cm3

Answer 1

Answer:

$n=1.86*10^{-30}m^3$

Explanation:

From the question we are told that:

Fermi energy of conduction electrons $E_f=0.548J$

Generally the equation for Fermi energy is mathematically given by

 $E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}$

 $E_f=\frac{3}{\pi}^2/3*\frac{h^2}{8m}*{n^{2/3}}$

 ${n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}$

Where

h= Planck's constant

 ${n^{2/3}}=\frac{E_f}{\frac{3}{\pi}^2/3*\frac{h^2}{8m}}$

 ${n^{2/3}}=\frac{0.548J}{3.62*10^{-19}}$

 $n=(1.51*10^{-20})^{3/2}$

 $n=1.86*10^{-30}m^3$