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oksano4ka [1.4K]
3 years ago
10

A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800 N on him. The

mass of the losing player + equipment is 90.0 kg, and he is accelerating at 1.20m/s2 backward. What is the force of friction between the losing player’s feet and the grass?
Physics
1 answer:
uysha [10]3 years ago
8 0

Answer:

f = 692 N

Explanation:

given data:

f =800N

a =1.2 m s^{2}

m= 90 kg

from newton's second law

net force F_{net} =\sum F = F_1 +F_2 +..... = ma

therefore we have from above equationF_{net} = F -f = ma

ma =F - f

putting all value to get force of friction

1.2*90 = 800 - f

f = 692 N

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<h3>What is half-life?</h3>

The time it takes for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life T1/2 and the decay constant is given by T1/2 = 0.693/λ.

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