At the start of the 0.266 s, the object's speed was 8.26 m/s.
The question can only be talking about speed, not velocity.
Answer:
The third drop is 0.26m
Explanation:
The drop 1 impacts at time T is given by:
T=sqrt(2h/g)
T= sqrt[(2×2.4)/9.8]
T= sqrt(4.8/9.8)
T= sqrt(0.4898)
T= 0.70seconds
4th drops starts at dT=0.70/3= 0.23seconds
The interval between the drops is 0.23seconds
Third drop will fall at t= 0.23
h=1/2gt^2
h= 1/2×9.81×(0.23)^2
h= 0.26m
Solution= The answer is true
I believe the correct answer from the choices listed above is the first option. Decreasing a telescope's eyepiece focal length will increase magnification. <span>The magnification of the </span>telescope<span> image is (</span>focal length<span> of the objective) divided by (</span>focal length <span>of the </span>eyepiece<span>). Hope this answers the question.</span>
Explanation:
Radiation biology is the study of the effects of ionizing radiation on living organisms, when this radiation is absorbed in biologic material, ionization and excitations occur in a pattern that depends on the type of radiation involved, considering how far the primary ionization events are separated in space, radiation can be sparsely ionizing (for example, an x-ray or a gamma-ray) or densely ionizing (for example, a proton or an alpha particles).
<em>DNA is the most critical biological target because of the limited redundancy of the genetic information it contains, most lesions are reparable, but those produced by densely ionizing radiation are generally less reparable than those produced by sparsely ionizing radiation. Densely ionizing (high LET) radiations, therefore, typically have a higher relative biological effectiveness.</em>
I hope you find this information useful and interesting! Good luck!
