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Tanya [424]
3 years ago
7

In a chemical equation, where do the products appear

Physics
1 answer:
tester [92]3 years ago
4 0

Answer:

products would appear after the raw materials

Explanation:

raw material + raw material = product (anything deriving from combining two materials)

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The count rate of a radioactive source decreases from 1600 counts per minute to 400 counts per minute in 12 hours. What is the h
kirill115 [55]

Answer:

t_{1/2}=6 h

Explanation:

Let's use the decay equation.

A=A_{0}e^{-\lambda t}

Where:

  • A is the activity at t time
  • A₀ is the initial activity
  • λ is the decay constant

We know that \lambda=\frac{ln(2)}{t_{1/2}}

So we have:

\lambda=\frac{ln(A/A_{0})}{t}

\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}

t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}

t_{1/2}=6 h

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

4 0
3 years ago
Consider the electronic elements that are cooled by forced convection in Problem 6.31. The cooling system is designed and tested
Stella [2.4K]

Answer:

surface temperature of the chip located 120 mm Ts=42.5°C

surface temperature of the chip in Mexico Ts=46.9°C

Explanation:

from the energy balance equation we have to:

q=E=30W

from Newton´s law:

Ts=Tα+(q/(h*A)), where A=l^2

N=h/k=0.04*(Vl/V)^0.85*Pr^1/3

data given:

l=0.12 m

v=10 m/s

k=0.0269 W/(m*K)

Pr=0.703

Replacing:

h=0.04*(0.0269/0.12)*(10*0.12)/((16*69x10^-6))^0.85*(0.703^1/3) = 107 W/m^2*K

The surface temperature at sea level is equal to:

Ts=25+(30x10^-3/107*0.004^2)=42.5°C

h=0.04*(0.0269/0.12)*((10*0.12)/(21*81x10^-6))^0.85*(0.705^1/3)=85.32 W/(m*K)

the surface temperature at Mexico City is equal to:

Ts=25+(30x10^-3/85.32*0.004^2)=46.9°C

8 0
3 years ago
Charging a balloon by rubbing it on wool is an example of
SVETLANKA909090 [29]
Electronic friction ^.^
3 0
3 years ago
Read 2 more answers
Static electricity occurs when electrons build up and _________
EleoNora [17]
Static electricity<span> is a </span>buildup<span> of </span>electric<span> charges on objects. Charges </span>build up<span> when negative </span>electrons<span> are transferred from one object to another. The object that gives </span>up electrons<span> becomes positively charged, and the object that accepts the </span>electrons<span> becomes negatively charged. This can </span>happen<span> in several ways</span>
5 0
3 years ago
In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.40 mm . what is the differenc
Strike441 [17]

The solution would be like this for this specific problem:

 

Given:  

diffraction grating slits = 900 slits per centimeter

interference pattern that is observed on a screen from the grating = 2.38m

maxima for two different wavelengths = 3.40mm

 

slit separation .. d = 1/900cm = 1.11^-3cm = 1.111^-5 m <span>

Whenas n = 1, maxima (grating equation) sinθ = λ/d 
Grant distance of each maxima from centre = y .. 
<span>As sinθ ≈ y/D  y/D = λ/d λ = yd / D </span>

∆λ = (λ2 - λ1) = y2.d/D - y1.d/D 
∆λ = (d/D) [y2 -y1] 

<span>∆λ = 1.111^-5m x [3.40^-3m] / 2.38m .. .. ►∆λ = 1.587^-8 m</span></span>

6 0
3 years ago
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