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3 years ago

Solve for m 5m +1 = -10m -19

Mathematics

2 answers:

musickatia [10]3 years ago

5 0

Answer:

m = $-\frac{4}{3}$ or $-\frac{20}{15}$

Step-by-step explanation:

<h2>How to solve:</h2><h3>5m + 1 = -10m - 19</h3><h3>Add 19 to each side to get:</h3><h3>5m + 20 = -10m</h3><h3>Then, subtract 5m to each side to get:</h3><h3>20 = -15m</h3><h3>Divide each side by -15m to get:</h3><h3>20/-15 = m</h3><h3>Leave it as is or simplify to -4/3</h3><h3 /><h3>Good Luck!</h3><h3 />

stich3 [128]3 years ago

4 0

Answer:

m= -4/3

Step-by-step explanation:

add 10m to each side and subtract 1 from both sides to change the equation to 15m=-20. Then divide 15 from both sides to get m alone. You will end up with -4/3

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1 year ago

Consider the equation x2+4x+9=0 in standard form. Which equation shows the coefficients a, b, and c correctly substituted into t

Afina-wow [57]

Answer:

Step-by-step explanation:

The general form of a quadratic equation is ax²+bx+c = 0

Given the quadratic equation x²+4x+9=0 in its standard form, on comparing with the general equation we can get the value of the constant a, b and c as shown;

ax² = x²

a = 1

bx = 4x

b = 4

c = 9

The quadratic formula is given as x = -b±√(b²-4ac)/2a

Substituting the constant;

x = -4±√(4²-4(1)(9))/2(1)

x = -4 ±√(16-36)/2

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x = -4±(√-1*√20)/2

Note that √-1 = i

x = -4±(i√4*5)/2

x = (-4±i2√5)/2

x = -4/2±i2√5/2

x = -2±i√5

The solution to the quadratic equation are -2+i√5 and -2i-√5

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3 years ago

Solve for m 5m +1 = -10m -19​

Solve for m 5m +1 = -10m -19