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3 years ago

Which statement is correct?

Mathematics

1 answer:

notsponge [240]3 years ago

7 0

Answer:

B. Cosecant is the reciprocal of sine

Step-by-step explanation:

Well, this is where you have to remember your reciprocal identities in your trigonometric identities!

So:

- Cosecant is the reciprocal of sine

- Secant is the reciprocal of cosine

- Cotangent is the reciprocal of tangent

How I remember them is just the co is with the non-co (cosecant with sine (no co there) and cosine with secant. Tangent with cotangent is pretty easy to remember.)

I'll attach a picture for trig identities! Let me know if you have any further questions :)

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At an outdoor party location, the tables seat 12 guests each. The party host invited 163 people and 9 people responded that they

Reil [10]

Answer:B

Step-by-step explanation:

3 0

3 years ago

Factor 1/2 out of 1/2x + 3/2

EastWind [94]

The answer to the question is:

−12(x−12)

7 0

3 years ago

Is this question a statistical question Which student spends the most time playing musical instruments? explain why or why not

Cloud [144]

Statistical questions are questions that are answered by collecting variable data, which can be given as an average/range/percentage. This question has a single answer, and therefore it is not a statistical question. A statistical question would be, for example, What is the average amount of time students in this class spend playing musical instruments?

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3 years ago

6.3.6. Among the early attempts to revisit the death postponement theory introduced in Case Study 6.3.2 was an examination of th

kakasveta [241]

Answer:

So the Null hypothesis is rejected in this case

Step-by-step explanation:

The number of celebrities is n = 348

So to solve this we would assume that p is the percentage of people that died on the month preceding their birth month

Generally if there is no death postponement then p will be mathematically evaluated as

$p = \frac{1}{12}$

This implies the probability of date in one month out of the 12 months

Now from the question we can deduce that the hypothesis we are going to be testing is

$Null Hypothesis \ \ H_0 : p = 0.083$

This is a hypothesis is stating that a celebrity dies in the month preceding their birth

$Alternative \ Hypothesis H_1 : p < 0.083$

This is a hypothesis is stating that a celebrity does not die in the month preceding their birth

is c is the represent probability for each celebrity which either c = 0 or c = 1

Where c = 0 is that the probability that the celebrity does not die on the month preceding his/ her birth month

and c = 1 is that the probability that the celebrity dies on the month preceding his/ her birth month

Then it implies that

for

n= 1 + 2 + 3 + .... + 348 celebrities

Then the sum of c for each celebrity would be $c_s = 16$

i.e The number of celebrities that died in the month preceding their birth month

We are told that the significance level is $\alpha = 0.05$ , the the z value of $\alpha$ is

$z_{\alpha } = 1.65$

This is obtained from the z-table

Since this test is carried out on the left side of the area under the normal curve then the critical value will be

$z_{\alpha } = - 1.65$

So what this implies is that $H_o$ will be rejected if

$z \le -1.65$

Here z is the test statistics

Now z is mathematically evaluated as follows

$z = \frac{c - np}{\sqrt{np_o(1- p_o)} }$

$z = \frac{16 - (348 *0.083)}{\sqrt{348*0.083 (1- 0.083)} }$

$z =-2.50$

From our calculation we see that the value of z is less than $-1.65$ so the Null hypothesis will be rejected

Hence this tell us that the evidence provided is not enough to conclude that 16 celebrities died a month to their birth month

8 0

3 years ago

The mean student loan debt for college graduates in Illinois is $30000 with a standard deviation of $9000. Suppose a random samp

Nataly [62]

Answer:

the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

Step-by-step explanation:

Given that:

Mean = 30000

Standard deviation = 9000

sample size = 100

The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:

$P(31000 < X < 33000) = P( X \leq 33000) - P (X \leq 31000)$

$P(31000 < X < 33000) = P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}} )- P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}} )$

$P(31000 < X < 33000) = P( Z \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}} )- P(Z \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}} )$

$P(31000 < X < 33000) = P( Z \leq \dfrac{3000}{\dfrac{9000}{10}}}) -P(Z \leq \dfrac{1000}{\dfrac{9000}{10}}})$

$P(31000 < X < 33000) = P( Z \leq 3.33)-P(Z \leq 1.11})$

From Z tables:

$P(31000 < X$

Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

8 0

3 years ago