Answer:
Explanation:
a ) V( primary ) = 100 V
V( secondary ) = 10 V
No of turns ( secondary ) / No of turns ( primary ) = 10 / 100
= 1 / 10
b ) current in secondary
= volt ( secondary ) / resistance
= 10 /6 = 1.67 A
c )
Average power to secondary
= V ( secondary ) x current ( secondary )
= 10 x 10 / 6
= 16.67 W
d )
Power in primary = power in secondary = 16.67 W
e ) current drawn by ac line ( primary )
Volt ( primary ) x current ( primary ) = power in primary
= 16.67
current ( primary )
= 16.67 / 100
= 0.167 A
Explanation:
It is given that,
Velocity of the electron, 
Magnetic field, 
Charge of electron, 
(a) Let 
is the force on the electron due to the magnetic field. The magnetic force acting on it is given by :
![F_e=1.6\times 10^{-19}\times [(2\times 10^6i+3\times 10^6j)\times (0.030i-0.15j)]](https://tex.z-dn.net/?f=F_e%3D1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%20%5B%282%5Ctimes%2010%5E6i%2B3%5Ctimes%2010%5E6j%29%5Ctimes%20%280.030i-0.15j%29%5D)
(b) The charge of electron, 
The force acting on the proton is same as force on electron but in opposite direction i.e (-k). Hence, this is the required solution.
Answer:
The potential difference between the ends of a wire is 60 volts.
Explanation:
It is given that,
Resistance, R = 5 ohms
Charge, q = 720 C
Time, t = 1 min = 60 s
We know that the charge flowing per unit charge is called current in the circuit. It is given by :
I = 12 A
Let V is the potential difference between the ends of a wire. It can be calculated using Ohm's law as :
V = IR
V = 60 Volts
So, the potential difference between the ends of a wire is 60 volts. Hence, this is the required solution.
