a battery of 5v and internal resistance of 5 ohms is connected to a resistor of 20 ohms. calculate the value of terminal voltage

Use the slider to apply a force of about 400 N. After 2 s have elapsed in the simulation, decrease the Applied Force (force exer

nikklg [1K]

Answer:

<em>c. decreasing.</em>

Explanation:

Force produces acceleration or deceleration. Force is the product of a body's mass and its acceleration. When a force is applied to an object, the force tends to cause the body to move if the body was originally stagnant, cause the body to accelerate if applied in the direction of the body's velocity, or decelerate the body if applied in opposite direction to the velocity of the body. <em>When the force that is exerted on a moving body is slowly reduced to zero, frictional forces between the body and the floor surface gradually decelerates the body. When this deceleration occurs, the velocity of the body gradually decreases t a stop.</em>

6 0

4 years ago

Un bloque de 20kg de masa se desplaza horizontalmente en la dirección de eje X por acción de una fuerza horizontal variable F =

zmey [24]

Answer:

a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.

b) La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.

Explanation:

a) El trabajo expermentado por el bloque ( $W$ ), medido en joules, es definida por la siguiente ecuación integral:

$W = \int\limits^{x_{max}}_ {x_{min}} F(x) \, dx$ (1)

Donde:

$x_{min}$ , $x_{max}$ - Posiciones mínima y máxima del bloque, medidos en metros.

$F(x)$ - Fuerza horizontal aplicada al bloque, medida en newtons.

Si conocemos que $F(x) = 6\cdot x$ , $x_{min} = 10\,m$ y $x_{max} = 20\,m$ , entonces el trabajo realizado por esta fuerza es:

$W = \int\limits^{20\,m}_{10\,m} {6\cdot x} \, dx$ (2)

$W = 6\int\limits^{20\,m}_{10\,m} x\, dx$

$W = 3\cdot x^{2}\left|\limits_{10\,m}^{20\,m}$

$W = 3\cdot [(20\,m)^{2}-(10\,m)^{2}]$

$W = 900\,J$

El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.

b) La rapidez final del bloque se determina mediante de Teorema del Trabajo y la Energía, es decir:

$W = K_{f}-K_{o}$ (3)

Donde son $K_{o}$ , $K_{f}$ las energías cinéticas traslacionales inicial y final, medidos en joules.

Al aplicar la definición de energía cinética traslacional, expandimos y simplificamos la ecuación como sigue:

$W = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})$ (4)

Donde:

$m$ - Masa del bloque, medido en kilogramos.

$v_{o}$ , $v_{f}$ - Rapideces inicial y final del bloque, medidos en metros por segundo.

$\frac{2\cdot W}{m} = v_{f}^{2}-v_{o}^{2}$

$v_{f} = \sqrt{\frac{2\cdot W}{m}+v_{o}^{2}}$

Si conocemos que $W = 900\,J$ , $m = 20\,kg$ y $v_{o} = \sqrt{10}\,\frac{m}{s}$ , entonces la rapidez final del bloque es:

$v_{f} = \sqrt{\frac{900\,J}{2\cdot (20\,kg)}+10\,\frac{m^{2}}{s^{2}} }$

$v_{f} \approx 5.701\,\frac{m}{s}$

La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.

6 0

3 years ago

How much work do you do when you lift a 100 N child 0.5 m?

Papessa [141]

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 100 × 0.5

We have the final answer as

Hope this helps you

8 0

3 years ago

If the switch is open but near the point of contact where it would close the circuit, a spark can arc across the switch. Is a sp

marysya [2.9K]

Answer:

Explanation:

According to Faraday's law, the suddenly collapsing magnetic flux will induce an emf in the circuit, the direction of which will be such as to maintain the current in the circuit to oppose the change in magnetic flux. The magnitude of this emf will be proportional to the rate of change in magnetic flux, so when you flick the switch quickly, the magnetic flux changes quickly resulting in a larger emf. This in turn creates a large electric field gradient across the contacts of the switch. If this is greater than the ionisation potential of the air, then the molecules of the air in the vicinity of the switch will partially ionise, allowing them to conduct electricity which is manifested as a 'spark' across the switch. Conversely, when you flick the switch gently (slowly), resulting potential gradient across the switch becomes smaller.

Furthermore, if the circuit is largely 'inductive' (such as an incandescent lamp, heater element, or electric motor) then it is more likely to produce a more visible spark when the circuit is opened, because the 'inductive' element(s) in the circuit are storing energy in the form of magnetic field(s), which results in higher induced emf when the field collapses.

3 0

3 years ago

Read 2 more answers

Myopia is a condition of the eye where the crystalline lens focuses the light rays to a position between the lens and the retina

aliya0001 [1]

Answer: concave lens

Explanation:

Myopia is a condition of the eye where someone can only see near distant object clearly but not far distant object.

Myopia is corrected using concave lens (diverging) in order to diverge the rays entering the eye thereby allowing the rays to be focused properly on the retina.

4 0

3 years ago