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Anna [14]
3 years ago
15

If a steel nail is wrapped 8 times with an insulated copper wire and each end of is attached to a 1.5 V battery, we find that it

will lift the weight of 2 large paper clips. We hypothesized that for each 8 coils, you will be able to pick up one additional paper clip. When we ran the experiment, we observed and recorded that when we added 8 more wraps around the nail (16 coils) we could lift 4 paper clips and when we added 8 more wraps (24 coils) we could lift 6 paper clips. Choose the correct conclusion to the experiment.
1. We redesign the test and hope for better results.
2. We concluded that every time we add 8 wraps to the nail the total number of paper clips lifted doubled.
3. We concluded that our original test flawed. Because of the results, 8 coils should be able to pick up 2 paper clips. We will check our original test with a fresh battery.
4. We concluded that something went wrong with the experiment since it didn't give us the results we expected.
Physics
2 answers:
sergejj [24]3 years ago
4 0

Answer:

2

Explanation:

i think that it would be 2 because it makes the most sense

ehidna [41]3 years ago
4 0
I believe it’s 2!

2.) we concluded that everytime we add 8 wraps to the nail the total number of paper clips lifted doubled.
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Superconductor, conductor, semiconductor, insulator
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3 years ago
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Mean arterial pressure is ________ (indirectly/directly) proportional to ________ and ________ (indirectly/directly) proportiona
g100num [7]

Answer: Mean Arterial Pressure is directly proportional to Cardiac Output and Systemic Vascular Resistance and also directly proportional to Central Venous Pressure.

Explanation: Based on the relationship of flow, pressure and resistance, the mean arterial pressure is determined by the cardiac output (CO), systemic vascular resistance (SVR), and central venous pressure (CVP). This relationship is given by:

MAP = (CO x SVR) + CVP

Which is alternatively expressed as:

MAP = CO x SVR (this is because at any point in time in blood circulation, the central venous pressure is always near to zero mmHg.

Due to this direct relationship, any factor affecting the cardiac output and the Systemic Vascular Resistance would cause a corresponding change in the Mean Arterial Pressure.

It is also worthy to note that If Cardiac Output and Systemic Vascular Resistance change reciprocally (inversely) and proportionately, then Mean Arterial Pressure will not change. The plotted graph is one of positive slope.

The whole relationship occurs when blood is pumped out of the left ventricle into the aorta and distributing arteries, creating pressure.

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3 years ago
A rainbow viewed from an airplane may form a complete circle. Where will the shadow of the airplane appear? Explain.
attashe74 [19]
The position of the sun must be at the horizon in order for the rainbow to appear.
The relative positions of the sun and plane make the rainbow appear as a full circle.
However, if the sun is at the horizon, the shadow of the plane will be behind the plane, not below it; this means that the shadow of the plane will not fall on the earth.
3 0
3 years ago
Global Precipitation Measurement (GPM) is a tool scientist use to forecast weather. Which statements describe GPM
klio [65]

Answer:

Correct answers:

Explanation:

• It is a satellite that collects data about rain and snow.

GPM is part of NASA's Earth Systematic Missions program and its function is to track precipitation from space with satellites and to provide accurate information of the time, place an amount of rain or snow anywhere in the world.

• Its orbit covers 90 percent of Earth's surface.

 GPM has unique perspective on measuring precipitation from space because of their collected satellite retrievals.

• The sensors measure microwaves.

GPM Microwave Imager (GMI) is a sensor that observes the microwave energy emitted by the Earth and atmosphere, so it improves the accuracy of rain and snowfall estimates.

6 0
4 years ago
Un campo eléctrico es creado por una carga eléctrica de 5 microcoulomb, a 35 cm se coloca una carga de prueba la cual es atraída
Sidana [21]

Answer:

Supongo que queremos determinar la carga de la carga de prueba.

Sabemos que la fuerza culombiana entre dos cargas q₁ y q₂, separadas por una distancia R, está dada por:

F = k_c*\frac{|q_1*q_2|}{R^2}

Aislandolo para una de las cargas, obtenemos:

\frac{F*R^2}{kc*|q_1|} =|q_2|

En este caso sabemos:

fuerza atractiva, por lo que los signos de las cargas son opuestos.

q₁  = 5 mC

R = 35cm

F = 1.5 N

Kc = 9*10^9 N*m^2/C^2

Un primer paso, seria reescribir todos los valores en las mismas unidades.

Sabiendo que:

100cm = 1m

R = 35cm = (35/100) m = 0.35m

Y sabiendo que:

1mc = 1*10^(-6) C

Entonces:

q₁  = 5 mC = 5*1*10^(-6) C = 5*10^(-6) C

Ahora podemos reemplazar esos valores en la ecuación de la fuerza, para obtener el valor de la otra carga:

\frac{15N*(0.35m)^2}{(9*10^9 N*m^2/C^2)*5*10^{-6}C} =|q_2| = 4.08*10^{-5} C

Y recordar que las cargas tienen signo opuesto, entonces la carga de la carga de prueba es:

q₂ = -4.08*10^-5 C

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3 years ago
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