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24x4y 3x-4y-1 Which of the following is the simplest form of the expression above? 8 8x-16y-1 8x-1y-1 8x8y2

beks73 [17]

8x8y2 would be the answer

3 0

4 years ago

A company produces mopeds and bicycles. It must produce at least 10 mopeds per month. The company has the equipment to produce o

zepelin [54]

Answer:

3. B. P = 134x + 20y

4. J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)

5. C. 60 mopeds 100 bicycles

Step-by-step explanation:

3. The given information are;

The number of mopeds the company must produce per month = 10

The number of mopeds the company can produce month = 60

The number of bicycles the company can produce per month = 120

The total sum of the produced mopeds and bicycles ≤ 160

The profit on a moped = $134

The profit on a bicycle = $20

Given that the number of moped produced = x and the number of bicycles produced = y

Therefore, we have;

Profit, P = $134 × x + $20 × y

Which gives;

B. P = 134x + 20y

4) From Desmos, using the following constraints;

x + y ≤ 160

10 ≤ x ≤ 60

0 ≤ y ≤ 120 we have;

The vertices of the constraint for the feasible region are;

J. (10, 150), I(40, 120), G(60, 100), C(60, 0) and E(10, 0)

5) We note that since the profit from each moped is more than the profit from the sale of each bicycle, the maximum possible number of moped should be produced, while the rest should be used to produce bicycles

Therefore, given that from the vertices, the maximum possible number of moped = 60, the number of bicycles to be produced should be 160 - 60 = 100 bicycles

Which gives;

C. 60 mopeds 100 bicycles.

8 0

3 years ago

The equation to convert from degrees Celsius to degrees Fahrenheit is F=1.8C+32, whereas a simpler estimate for this conversion

anygoal [31]

Answer:

The answer to your question is Equation 1 C = (F -32)/1.8

Equation 2 C = (F - 30)/2

Step-by-step explanation:

Data

Equation 1 F = 1.8C + 32

Equation 2 F = 2C + 30

Solve both equations for C

Equation 1

- Substract 32 in both sides

F - 32 = 1.8C + 32 - 32

- Simplify

F - 32 = 1.8C

- Divide both sides by 1.8

C = (F -32)/1.8

Equation 2

F = 2C + 30

- Substract 30 in both sides

F - 30 = 2C + 30 - 30

- Simplify

F - 30 = 2C

- Divide both sides by 2

C = (F - 30)/2

7 0

3 years ago

What is the area of the green shaded part?

Mandarinka [93]

Answer:

$7.74 \: {cm}^{2}$

Step-by-step explanation:

Area of the green shaded part

= Area of square with side 6 cm - Area of circle with radius (6/2=3) 3 cm.

$= {side}^{2} - \pi {r}^{2} \\ = {6}^{2} - 3.14 \times {3}^{2} \\ = 36 - 28.26 \\ = 7.74 \: {cm}^{2}$

8 0

3 years ago

Suppose a production line operates with a mean filling weight of 16 ounces per container. Since over- or under-filling can be da

miss Akunina [59]

Answer:

From the question we are told that

The population mean is $\mu = 16$

The sample size is n = 30

The sample mean is $\= x = 16.32$

The population standard deviation is $\sigma = 0.8$

The level of significance is $\alpha = 0.10$

Step 1: State hypotheses:

The null hypothesis is $H_o : \mu = 16$

The alternative hypothesis is $H_a : \mu \ne 16$

Step 2: State the test statistic. Since we know the population standard deviation and the sample is large our test statistics is

$t = \frac{ \= x -\mu }{ \frac{\sigma}{ \sqrt{n} } }$

=> $t = \frac{ 16.32 -16 }{ \frac{0.8 }{ \sqrt{30} } }$

=> $t =2.191$

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 30 - 1$

=> $df =29$

Step 3: State the critical region(s):

From the student t-distribution table the critical value corresponding to $\alpha = 0.10$ is

$t = 1.311$

Generally the critical regions is mathematically represented as

$- 1.311 < T < 1.311$

Step 4: Conduct the experiment/study:

Generally the from the value obtained we see that the t value is outside the critical region so the decision is [Reject the null hypothesis ]

Step 5: Reach conclusions and state in English:

There is sufficient evidence to show that the filling weight has to be adjusted

Step 6: Calculate the p-value associated with this test. How does this the p-value support your conclusions in Step 5?

From the student t-distribution table the probability value to the right corresponding to $t =2.191$ at a degree of freedom of $df =29$ is

$P( t > 2.191) = 0.0183$

Generally the p-value is mathematically represented as

$p-value = 2 * P( t > 2.191 )$

=> $p-value = 2 * 0.0183$

=> $p-value = 0.0366$

Generally looking at the value obtained we see that $p- value < \alpha$ hence

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

4 0

3 years ago