Answer:
y=a(x+4)^2 +1, for a real number a hat is different of 0.
Step-by-step explanation:
If we know only the vertex, there are many quandratic equations.
* Result: Vertex (m,n), the quadratic equation is y= a(x-m)^2 + n for a real number a that is different of 0.
Here, the vertex (-4,1), we have the equation: y=a(x+4)^2 +1, for a real number a hat is different of 0.
Hope you understand.
Answer:
-3-2+3=-2
Step-by-step explanation:
A-2+3=-2
-3 -3
A-2=-5
+2 +2
A=-3
So, A-2+3=-2 is now -3-2+3=-2
The equation of the line that is perpendicular to y = -5/2 x + 1 and passing through (10, 3) will be y = 2/5 x + 1.
<h3>What is the linear system?</h3>
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
The equation of the perpendicular line will be given as
y = mx + c
The given equation is y = -5/2 x + 1.
The slope of the line is -5/2.
Then the product of the slope of the perpendicular lines is a negative one.
-5/2 × m = - 1
m = 2/5
Then the equation will be
y = 2/5 x + c
Then the equation is passing through (10, 3). Then we have
3 = 2/5 × 10 + c
3 = 2 + c
c = 1
Then the equation is y = 2/5 x + 1.
More about the linear system link is given below.
brainly.com/question/20379472
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I think it’s 22 or 23...I’m so sorry if it’s wrong :/
