Answer:
D, 120 , In order obtuse acute right,
Step-by-step explanation:
the fourth one dosent have options so I cant answer that ( It can be anything other than ZMD and DMZ)
A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
is differentiable across its domain, so the MVT says there is some value of
in the open interval
such that
You have
so the equation above becomes
Solve for
.
so
is indeed the average of the endpoints, i.e. the midpoint.
You are post to find 110 minus the other number and you will get x
Ok so, the quotient of a number y and 22, we would solve this problem like this... y:22, and y:22 is equal to 7/22, therefore, the quotient of a number y and 22 would be.
