For number one you should get 6√3
Answer:
196 in ^2
Step-by-step explanation:
Formula for area of trapezium is h ( a + b )/ 2 so.....
14(10 + 18)/2=196
Hope this helps <span>1) </span><span>Equations with negative values for a</span><span> produce graphs that open down and equations with a positive values for a</span> produce graphs that open up.
<span>2)<span> </span></span><span>As the absolute value of a gets larger our graphs become more narrow (they shoot towards positive or negative infinity faster). This is more interesting than it might appear. If you consider the second derivative of any quadratic it will be the a</span><span> value. The second derivative represents acceleration, so the larger the a value the faster the increase of velocity and accordingly a quicker progression towards positive or negative infinity. Check this out in graphing calculator, press play to vary the value of a from -20 to 20. Notice that when the value of a approaches zero, the approximates a line, and of course when a is 0 we have the line y</span><span> = 2x</span><span> – 1.</span>
Answer:
(x+3)/(x-4)
Step-by-step explanation:
[2x²/(x-4)(x-3)] - [x²+9/(x-4)(x-3)] =
(x²-9)/(x-4)(x-3) =
(x+3)(x-3)/(x-4)(x-3) =
x+3/x-4
BC = 12; XZ = 8; BZX = 55
To find BC:
Since XY is the bisector of AB and AC, this means that it is a median of triangle ABC. Its length will be half of the length of BC; 6 = 1/2BC; 6*2 = BC; 12 = BC
To find XZ:
Since XZ is the bisector of AB and BC, this means that it is a median of triangle ABC. Its length will be half of the length of AC; 1/2(16) = 8.
To find BZX:
XYCZ is a parallelogram. Consecutive angles of a parallelogram are supplementary; 180-55=125=XZC.
XZC and BZX form a linear pair and are thus supplementary. This means that BZX = 180-XZC = 180-125 = 55
