The polynomial
may have solutions which are the divisors of -20, therefore -20 has the following divisors:
.
If x=1, then
,
if x=-1, then
,
if x=2, then
, then x=2 is a solution and you have the first factor (x-2).
If x=-2, then
, then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of
, then the polynomial
is a divisor of
and dividing the polynomial
by
you obtain
.
Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
Answer:
A = 34.84
Step-by-step explanation:
6.7 * 5.2 = 34.84
Answer:
B
Step-by-step explanation:
