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Komok [63]
3 years ago
12

Rectangle rhombus square isosceles trapezoid

Mathematics
1 answer:
timofeeve [1]3 years ago
7 0

Answer:

Rhombus

Step-by-step explanation:

It does not have congruent diagonals

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Math work pls help :)​
solong [7]

Answer:

the theorum used here is sas one

8 0
3 years ago
5. Consider the following equations.
WITCHER [35]

Answer:

Step-by-step explanation:

In y = mx + b form, the slope can be found in the m position and the y intercept can be found in the b position.

4x - 2y = -6

-2y = -4x- 6

y = (-4/-2)x -(6/-2)

y = 2x + 3....slope here is 2, and y int is 3

3x + y = 3

y = -3x + 3.....slope here is -3, and y int is 3

B. slopes are different, y intercepts are the same

3 0
3 years ago
PPPPPPPPPPPLLLLLLLLLLLLLLLLZZZZZZZZZZZZZZ
svlad2 [7]
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer

Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)

4 0
3 years ago
In the standard (x, y) coordinate plane, what is the distance, in coordinate units, between (-3, -2) and (5, 5)?
Sav [38]

Answer:

10.630

Step-by-step explanation:

\sqrt(x_{2}  -x_{1})^{2} + (y_{2} -y_{1})^{2}

\sqrt( 5-(-3)^{2} + (5- (-2)^{2}

(5 - ( - 3)^2 = 64

(5 - ( -2)^2 = 49

49 + 64

113

\sqrt113

10.630


I hope this helps

8 0
3 years ago
Which of these can not form a perpendicular bisector?v PLZ HALLLLPPPP
polet [3.4K]
A circle obviously. A perpendicular bisector requires right angles which a circle can physically never have.
4 0
4 years ago
Read 2 more answers
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