<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Opposite sides of a parallelogram are congruent.
3x+ 2= 4x-3
Subtract 3x from both sides
2= x -3
Add 3 to both sides
5= x
2y+7=4y-9
Subtract 2y from both sides
7= 2y -9
Add 9 to both sides
16 = 2y
Divide by 2 on both sides
8 = y
Answer:
step three
Step-by-step explanation:
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