Answer:
y = 2
Step-by-step explanation:
6y - 5 = 7
~Add 5 to both sides
6y = 12
~Divide 6 to both sides
y = 2
Best of Luck!
All you have to do it combine one pair of like terms with eachother for each time you move further on the pyramid.
PYRAMID A :
1ST LINE : -2x + 3
2ND LINE : -9x + 6 and 7x - 4
3RD LINE : 3x - 4 and -12x + 10 and 7x - 4
4TH LINE : 2x - 3 and x - 1 and -12x + 10 and 7x - 4
5TH LINE : -6x + 0 and 8x - 3 and x - 1 and -12x + 10 and 7x - 4.
6TH LINE : 2x - 6 and -8x + 6 and 8x - 3 and x - 1 and -12x + 10 and 7x - 4
7TH LINE : (we'll combine the first two terms from below) -1x - 2 and 3x - 4 and -8x + 6 and 8x - 3 and x - 1 and -12x + 10 and 7x - 4.
8TH LINE : it's already given in Pyramid A.
. . .
PYRAMID B :
1ST LINE : 2x - 3y - 6
2ND LINE : 4x - 2y - 5 and -2x - y - 1
3RD LINE : 5x - y - 5 and -x - y and -2x - y - 1
4TH LINE : -x + 2y - 3 and 6x - 4y - 2 and -x - y and -2x - y - 1
5TH LINE : -2x + 2y - 3 and x + y and 6x - 4y - 2 and -x - y and -2x - y - 1
6TH LINE : 2x + 3y - 4 and -4x - y + 1 and x + y and 6x - 4y - 2 and -x - y and -2x - y - 1
7TH LINE : 3x + y + 8 and -x + 2y + 4 and 4x - y + 1 and x + y and 6x - 4y - 2 and -x - y and -2x - y - 1
8TH LINE : given in the attachment, Pyramid B
Answer:
![(x+6)^2 +(y+10)^2 = 324](https://tex.z-dn.net/?f=%28x%2B6%29%5E2%20%2B%28y%2B10%29%5E2%20%3D%20324)
Step-by-step explanation:
![\underline{\textbf{Equation of circle(Standard form)}}\\\\~~~~~~~~~~~~~~~~~~~~(x-h)^2 + (y-k)^2 =r^2\\\\\text{Where,}\\\\(h,k) = \text{Center of the circle.}\\\\r = \text{Radius of the circle.}\\](https://tex.z-dn.net/?f=%5Cunderline%7B%5Ctextbf%7BEquation%20of%20circle%28Standard%20form%29%7D%7D%5C%5C%5C%5C~~~~~~~~~~~~~~~~~~~~%28x-h%29%5E2%20%2B%20%28y-k%29%5E2%20%3Dr%5E2%5C%5C%5C%5C%5Ctext%7BWhere%2C%7D%5C%5C%5C%5C%28h%2Ck%29%20%3D%20%5Ctext%7BCenter%20of%20the%20circle.%7D%5C%5C%5C%5Cr%20%3D%20%5Ctext%7BRadius%20of%20the%20circle.%7D%5C%5C)
![\underline{\textbf{Solution:}}\\\\\text{Given that,}\\\\\text{Center of the circle,}~ (h,k) = (-6,-10)\\\\\text{Radius of the circle,}~ r = 18~ \text{units.}\\\\\text{From the given data, the equation of the circle is,}\\\\~~~~~~~~~~~~~~~~~~~~(x-h)^2 +(y-k)^2 = r^2\\\\~~~~~~~~~~~\implies (x-(-6))^2+ (y-(-10))^2 = 18^2\\\\~~~~~~~~~~~\implies \boxed{(x+6)^2 +(y+10)^2 = 324}](https://tex.z-dn.net/?f=%5Cunderline%7B%5Ctextbf%7BSolution%3A%7D%7D%5C%5C%5C%5C%5Ctext%7BGiven%20that%2C%7D%5C%5C%5C%5C%5Ctext%7BCenter%20of%20the%20circle%2C%7D~%20%28h%2Ck%29%20%3D%20%28-6%2C-10%29%5C%5C%5C%5C%5Ctext%7BRadius%20of%20the%20circle%2C%7D~%20r%20%3D%2018~%20%5Ctext%7Bunits.%7D%5C%5C%5C%5C%5Ctext%7BFrom%20the%20given%20data%2C%20the%20equation%20of%20the%20circle%20is%2C%7D%5C%5C%5C%5C~~~~~~~~~~~~~~~~~~~~%28x-h%29%5E2%20%2B%28y-k%29%5E2%20%3D%20r%5E2%5C%5C%5C%5C~~~~~~~~~~~%5Cimplies%20%28x-%28-6%29%29%5E2%2B%20%28y-%28-10%29%29%5E2%20%3D%2018%5E2%5C%5C%5C%5C~~~~~~~~~~~%5Cimplies%20%5Cboxed%7B%28x%2B6%29%5E2%20%2B%28y%2B10%29%5E2%20%3D%20324%7D)
Answer:
<em>x</em>>2
Step-by-step explanation:
The first thing you need to do is distribute.
2 time 5 and 2 time -3x; -4 times 3 and -4 times -x.
After that you would get 10-6x < x-12+4x.
Now combine like terms. The only like terms are on the right side: x and 4x.
Now it's 10-6x < 5x-12.
Now put <em>x</em><em> </em>on one side. I prefer to work with a positive <em>x</em> so I would move it to the right.
Now it's 10 < 11x-12.
Isolate the <em>x</em><em>.</em><em> </em>Move the -12 first
Now it's 22<11x.
Divide by 11 next.
Now it's 11<x.
Switch it around so it's easier to interpret for the graph.
Final written inequality is x>11.
Graph the line x= 11 but with a dotted line because it is not equal to 11.
Color in everything to the right of the line because everything greater than x is to the right.