When point J (-14,6) is rotated 180 degrees around the origin, what is the resulting point J'? a (14,-6) b (-14,6) c (14,6) d (-
1 answer:
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Answer:
N(x) = 40 - 2x
P(x) = -2x² + 52 x - 240
maximum profit = 13
Step-by-step explanation:
given data
feeder cost = $6
average sell = 20 per week
price = $10 each
solution
we consider here price per feeder = x
and profit per feeder id here formula = x - 6
so that here
total profit will be
P (x) = ( x - 6 ) Nx
here N(x) is number of feeders sold at price = x
so formula for N (x) is here
N(x) = 20 - 2 ( x - 10 )
N(x) = 40 - 2x
so that
P(x) = (x-6) ( 40 - 2x)
P(x) = -2x² + 52 x - 240
since here
a = -2
b = 52
c = -240
a < 0
so quadratic function have maximum value of c -
so it will be
maximum value = -240 -
maximum value = 98
so here maximum profit attained at
x =
x =
x = 13
maximum profit = 13
Answer:
1st option
Step-by-step explanation:
let y = f(x) and rearrange making x the subject
y = 2x + 1 ( subtract 1 from both sides )
y - 1 = 2x ( divide both sides by 2 )
= x
Change y back into terms of x with x being the inverse h(x)
h(x) = =
x -