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3 years ago

13

When point J (-14,6) is rotated 180 degrees around the origin, what is the resulting point J'? a (14,-6) b (-14,6) c (14,6) d (-

14,-6)

1 answer:

elena55 [62]3 years ago

6 0

Answer:

$J' = (14,-6)$

Step-by-step explanation:

Given

$J = (-14,6)$

$R_0 = 180^\circ$

Required

Determine J'

When a point (x,y) is rotated 180 degrees around the origin, the new point is (-x, -y).

So:

$J = (-14,6)$

$J' = (14,-6)$

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inna [77]

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4 years ago

Look at the graph shown below:

ElenaW [278]

So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

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% (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
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\\\\\\
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\textit{plug in the values for }
\begin{cases}
y_1=4\\
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m=\boxed{?}
\end{cases}\\
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once you get the slope and solve for "y", that'd be the equation of the line.

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3 years ago

Find (f*g)(x) when f(x)=x^2-7x+12 and g(x)=3/x^2-16

IgorC [24]

The answer is: $(f*g)(x)= \frac{3x-9}{x+4}$

<u><em>Explanation</em></u>

Given functions are.......

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3 years ago

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4 years ago