Answer:
$311.20
Step-by-step explanation:
Here we are required to use the Compound interest formula for finding the Amount at the end of 9th year
The formula is given as
Where ,
A is the final amount
P is the initial amount = $200
r is the rate of interest = 5% annual = 0.05
n is the frequency of compounding in a year ( Here it is compounding monthly) = 12
t is the time period = 9
Now we substitute all these values in the formula and solve for A
Hence the amount after 9 years will be $311.20
It is d, -8.-5. I did it on paper
Answer:
A).Amount = $218250
B). Amount = $88700
Step-by-step explanation:
A) .$5000 in an account at age 23, and withdraw it 42 years
Number of years t= 42 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 42
A= p(1+r/n)^(nt)
A= 5000(1+0.09/42)^(42*42)
A= 5000(1+0.002143)^(1764)
A= 5000(1.002143)^1764
A= 5000(43.65)
A= 218250
Amount = $218250
B).waits 10 years before making the deposit, so that it stays in the account for only 32 years
Number of years t= 32 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 32
A= p(1+r/n)^(nt)
A= 5000(1+0.09/32)^(32*32)
A= A= 5000(1+0.0028125)^(1024)
A= 5000(1.0028125)^1024
A= 5000(17.74)
A= 88700
Amount = $88700
Answer:
18x = 7.2
x =.4
Step-by-step explanation:
Let x = the weight of one box
We have 18 boxes that weigh 7.2 lbs
18x = 7.2
Divide each side by 18
18x/18 = 7.2/18
x =.4
Simplified answer would be 60k^2+k
and you get that answer by combining like terms, Good Luck!
