Answer:
It's simply just subtract the these two numbers
451,202
- 239,021
= 212,181
Hope u doubt is cleared
to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient


Answer:
<h2>7y² - 6y -17</h2>
Step-by-step explanation:
(-2y^2-11y-7)-(-9y^2-5y+10) (firstly, we remove the brackets)
-2y^2 - 11y - 7 + 9y^2 + 5y - 10
= (-2y^2 + 9y^2) + (-11y + 5y) + (-7 - 10)
= (7y²) + (-6y) + (-17)
Answer:
b
Step-by-step explanation:
my teacher went over the same on with me