9514 1404 393
Answer:
32°, 58°
Step-by-step explanation:
The second angle is (3x-38), and their sum is ...
x +(3x -38) = 90
4x = 128 . . . . . . . . . add 38 and simplify
x = 32 . . . . . first angle
3x -38 = 3·32 -38 = 58 . . . . . . second angle
The measures of the two angles are 32° and 58°.
Answer:
$94
Step-by-step explanation:
Let the price of a bowl, a pan and a dish be $b, $p and $d respectively.
14b +9p +12d= 135 -----(1)
10b +6p +8d= 88 -----(2)
Subtracting equation (1) with equation (2):
14b +9p +12d -(10b +6p +8d)= 135 -88
Expand:
14b +9p +12d -10b -6p -8d= 47
4b +3p +4d= 47
Multiply both sides by 2:
8b +6p +8d= 47(2)
8b +6p +8d= 94
Thus, the price of 8 bowls, 6 pans and 8 dishes is $94.
Answer:
4 kg
Step-by-step explanation:
........................
4. Just look at the graph, and see which coordinates are on the line.
D, E, and F are on the line.
5. The y-coordinate is <em>(0,4)</em>, and the slope is (4 + 8)/(0 - 4) = <em>-3</em>. Therefore, the equation of the line is <em>y = -3x + 4</em>. Plugging in the numbers we know gives us <em>b = -3*8 + 4</em>. b = -20.
6. Find the number of times P is on a line. There are two lines that do so.
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let
P
P be the student population and
n
n be the number of years after 2013. Using the explicit formula for a geometric sequence we get
P
n
=
2
8
4
⋅
1
.
0
4
n
P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
2
0
2
0
−
2
0
1
3
=
7
2020−2013=7
We are looking for the population after 7 years. We can substitute 7 for
n
n to estimate the population in 2020.
P
7
=
2
8
4
⋅
1
.
0
4
7
≈
3
7
4
P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.