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Butoxors [25]
3 years ago
14

What is the measure of ∠x?

Mathematics
1 answer:
svp [43]3 years ago
6 0

Answer:

139

Step-by-step explanation:

Substract 41 from 180 assuming line LN is a straight line. the angles are supplementary

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Lemur [1.5K]

In a fraction or decimal


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4 years ago
dr. wong can see 9 patients in 3 hours, at this rate how long willl it take dr too see 72 patients?  PLEASE HELP!!!
Nataly [62]
How many times must he see 9 in order to cover all 72 of them ? 72/9 = 8 . He has to see 9 patients 8 times, so he has to work 3 hours 8 times. 3x8=24 hours.
6 0
3 years ago
Read 2 more answers
The rod is made of A-36 steel and has a diameter of 0.22 in . If the rod is 4 ft long when the springs are compressed 0.7 in . a
ziro4ka [17]

The force in the rod when the temperature is 150 °F is 718.72 pounds-force.

<h3>How to determine the resulting the resulting force due to mechanical and thermal deformation</h3>

Let suppose that rod experiments a <em>quasi-static</em> deformation and that both springs have a <em>linear</em> behavior, that is, force (F), in pounds-force, is directly proportional to deformation. Then, the elongation of the rod due to <em>temperature</em> increase creates a <em>spring</em> deformation additional to that associated with <em>mechanical</em> contact.

Given simmetry considerations, we derive an expression for the <em>spring</em> force (F), in pounds-force,  as a sum of mechanical and thermal effects by principle of superposition:

F = k\cdot (\Delta x + 0.5\cdot \Delta l)   (1)

Where:

  • k - Spring constant, in pounds-force per inch.
  • \Delta x - Spring deformation, in inches.
  • \Delta l - Rod elongation, in inches.

The <em>rod</em> elongation is described by the following <em>thermal</em> dilatation formula:

\Delta l = \alpha \cdot L_{o}\cdot (T_{f}-T_{o})   (2)

Where:

  • \alpha - Coefficient of linear expansion, in \frac{1}{^{\circ}F}.
  • L_{o} - Initial length of the rod, in inches.
  • T_{o} - Initial temperature, in degrees Fahrenheit.
  • T_{f} - Final temperature, in degrees Fahrenheit.

If we know k = 1000\,\frac{lb}{in}, \Delta x = 0.7\,in, \alpha = 6.5\times 10^{-6}\,\frac{1}{^{\circ}F}, L_{o} = 48\,in, T_{o} = 30\,^{\circ}F and T_{f} = 150\,^{\circ}F, then the force in the rod at final temperature is:

F = \left(1000\,\frac{lb}{in} \right)\cdot \left[0.7\,in + 0.5\cdot\left(6.5\times 10^{-6}\,\frac{1}{^{\circ}F} \right)\cdot (48\,in)\cdot (150\,^{\circ}F-30\,^{\circ}F)\right]

F = 718.72\,lbf

The force in the rod when the temperature is 150 °F is 718.72 pounds-force. \blacksquare

To learn more on deformations, we kindly invite to check this verified question: brainly.com/question/13774755

3 0
3 years ago
-7a-3&lt;2a <br> Please solve
rusak2 [61]

Answer:

a>-1/3

Step-by-step explanation:

-7a-2a<3

-9a<3

-a<3/9

a>-3/9

a>-1/3

You switch the sign because your dividing by a negative.

4 0
3 years ago
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I really need help with these questions 5. Wesley subscribes to telecommunications company's movie package The plan includes a b
Tanya [424]

Answer:

20 movies ; $70

Step-by-step explanation:

Company 1:

Monthly charge = $40 ; additional = 1.5 per movie

Let number of movies = x ; t = cost

Equation 1:

y = 40 + 1.5x

Company 2:

Monthly charge = $30

Additional = $2 per movie

Equation 2:

y = 30 + 2x

1) for equation 1 = equation 2

40 + 1.5x = 30 + 2x

40 - 30 = 2x - 1.5x

10 = 0.5x

x = 10/0.5

x = 20

Hence, 20 movies

B.)

y = 30 + 2x

y = 30 + 2(20)

y = 30 + 40

y = $70

7 0
3 years ago
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