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Korvikt [17]
3 years ago
7

You are dealt one card from a standard deck of 52 cards.

Mathematics
1 answer:
natima [27]3 years ago
8 0

Answer:

Can u please say the other number

Step-by-step explanation:

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10 + (2 x 3)2 ÷ 4 × 1 over 2 to the power of 3
Zielflug [23.3K]

Answer:

1.4375

Step-by-step explanation:

\frac{10 + (2 x 3)^{2} / (4)(1)}{2^{3}} \\

\frac{10 + (6)^{2} /4}{8} \\

\frac{10 + 36 / 4}{8} \\

\frac{46 /4}{8} \\ = \frac{11.5}{8} \\

7 0
2 years ago
8. Fifty students are trying to raise at least $12.500 for a class trip. They
lions [1.4K]

Answer: Each student should raise $225

Step-by-step explanation:

$12,500-$1,250= $11,250

$11,250/50= $225

Check answer:

$225x50= $11,250

7 0
3 years ago
If f(x) = x^3-2x, find f(-2).
kaheart [24]

Answer:

f(-2) = -4

Step-by-step explanation:

f(x) = x^3-2x,

Let x = -2

f(-2) = (-2)^3 - 2(-2)

       = -8 +4

        = -4

8 0
3 years ago
Read 2 more answers
Answer choices <br> 50%<br> 60%<br> 65%<br> If you put a link I will report
hodyreva [135]

Answer:

50%

Step-by-step explanation:

6 0
3 years ago
One number is three more than twice another, the sum of the numbers is 12. find the two numbers
Alenkasestr [34]
The numbers are:  "3" and "9" .
_______________________________________________________
Explanation:
_______________________________________________________
Let "x" represent one of the two (2) numbers.

Let "y" represent the other one of the two (2) numbers.

x = 2y + 3  ;

x + y = 12 .
__________________________
Method 1)
__________________________
x = 12 <span>− y ; 

Plug this into "x" for "2y + 3 = x" ;

</span>→ 2y + 3 = 12 <span>− y ; 
</span>
Add "y" to each side of the equation; & subtract "3" from each side of the equation ;

→ 2y + 3 + y − 3 = 12 − y + y <span>− 3 ;
</span>
to get:  3y = 9 ;

Divide each side of the equation by "3" ; 
to isolate "y" on one side of the equation; & to solve for "y" ;

             3y / 3 = 9 / 3 ;

               y = 3 .
____________________________
Now:  x = 12 − y ;  Plug in "3" for "y" ; to solve for "x" ;

    →   x = 12 − 3 = 9
____________________________
So;  x = 9,  y = 3 .
____________________________
Method 2) 
____________________________
When we have:
____________________________
x = 2y + 3  ;

x + y = 12 .
____________________________
 →  y = 12 − x ;
_____________________________
Substitute "(12−x)" for "y" in the equation:

" x = 2y + 3 " ;

→ x = 2(12 − x) + 3 ; 
_____________________________________
Note the "distributive property of multiplication" :
_____________________________________
  a(b + c) =  ab + ac ;

  a(b − c) = ab − ac ;
_____________________________________
As such:
_____________________________________
     →  2(12 − x) = 2(12) − 2(x) = 24 − 2x ; 
_____________________________________
So; rewrite:
_____________________________________
        x = 2(12 − x) + 3 ;
as:
_____________________________________
  →  x = 24 − 2x + 3 ;

  →  x = 27 − 2x ;

Add "2x" to each side of the equation:

 →  x + 2x = 27 − 2x + 2x ;

 →  3x = 27 ;

Divide each side of the equation by "3" ;
    to isolate "x" on one side of the equation; & to solve for "x" ;

      3x / 3 = 27 / 3 ;

        x = 9 .
___________________________
Note:  "y = 12 − x" ;  Substitute "9" for "x" ; to solve for "y" ;

→  y = 12 − 9 = 3 ;

→  y = 3 .
__________________________
So,  x = 9 ; and y = 3.
____________________________
The numbers are:  "3" and "9" .
_____________________________
To check our answers:
Let us plug these numbers into the original equations;
   to see if the equations hold true ; (i.e. when, "x = 9" ; and "y = 3"
_____________________________
  → x + y = 12 ; 

   → 9 + 3 =? 12 ?  Yes!
_____________________________
 
   → x = 2y + 3 ;

   → 9 =? 2(3) + 3 ?? ; 

   → 9 =?  6 + 3 ?  Yes!!
_____________________________

3 0
3 years ago
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