Given:
In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.
To find:
The measures of the 2 acute angles of the triangle.
Solution:
Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,
Divide both sides by 3.
The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:
Therefore, the measures of two acute angles are 26° and 64° respectively.
The mistake is n third line - adding 3w
96 + 2w =2(80 - 3w)
96 + 2w = 160 - 6w
+ 6w + 6w
96 + 8w = 160
- 96 -96
8w = 64
w = 8 weeks answer
Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } 
This area is equal to 125 as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒ 
- 18 a +80 -125 =0
⇒ - 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a 
4.
Thus the required answer is 15 cm.
Answer:
1,500 tickets in total (375 adult tickets and 1,125 children tickets)
Step-by-step explanation:
Let x be the number of adult tickets sold.
Three times as many children tickets were sold as adults, so 3x is the number of children tickets sold.
Children tickets were three dollars, so 3x children tickets cost 
Adult tickets were seven dollar, so x adult tickets cost 
The school sold $6000 worth of tickets.
Hence,
