Peter rolls 2 fair dica and adds tje result from each.worl out the probability of getting a total of 11

Mathematics

1 answer:

devlian [24]2 years ago

8 0

Answer:

6/11

Step-by-step explanation:

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Identify the values a, b, and c is the first step in using the quadratic formula to find the solution(s) to a quadratic equation

zlopas [31]

The values are a = 7, b = -9, c = -18.

Step-by-step explanation:

The given quadratic equation is $7x^{2} - 9x = 18$

The general form of the quadratic equation is $ax^{2} + bx + c = 0$

where,

a is the coefficient of x².
b is the coefficient of x.
c is the constant term.

Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.

So, bring the constant term 18 to the left side of the equation for equating it to zero.

⇒ $7x^{2} - 9x - 18 = 0$

Compare the above equation with general form $ax^{2} + bx + c = 0$

⇒ a = 7

⇒ b = -9

⇒ c = -18

Therefore, the values of a, b, and c are 7, -9 and -18.

7 0

3 years ago

Read 2 more answers

Based on data collected from its production processes, Crosstiles Inc. determines that the breaking strength of its most popular

alexandr1967 [171]

Answer:

16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.

Step-by-step explanation:

We are given that the breaking strength of its most popular porcelain tile is normally distributed with a mean of 400 pounds per square inch and a the standard deviation of 12.5 pounds per square inch.

Let X = the breaking strength of its most popular porcelain tile

SO, X ~ Normal( $\mu=400,\sigma^{2}=12.5^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean breaking strength of porcelain tile = 400 pounds per square inch

$\sigma$ = standard deviation = 12.5 pounds per square inch

Now, probability that the popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch is given by = P(X > 412.5)

P(X > 412.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{412.5-400}{12.5}$ ) = P(Z > 1) = 1 - P(Z $\leq$ 1)